在网上看到不错的 排名语句
select a,sum(b),rank() over(order by sum(b) desc) rn from test_06 group by a;
select a,sum(b),row_number() over(order by sum(b) desc) rn from test_06 group by a
rank在出现相同排名时序号是相同的,row_number返回的是一个连续递增的序号
select a,sum(b),rank() over(order by sum(b) desc) rn from test_06 group by a;
select a,sum(b),row_number() over(order by sum(b) desc) rn from test_06 group by a
rank在出现相同排名时序号是相同的,row_number返回的是一个连续递增的序号
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