实验四

实验任务 1

task1_1.c

task1_1.c
#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 4
int main()
{
    int a[N] = { 1,9,8,4 };
    char b[N] = { '1','9','8','4' };
    int i;
    printf("sizeof(int)=%d\n", sizeof(int));
    printf("sizeof(char)=%d\n", sizeof(char));
    printf("\n");
    //输出一维int数组a中每个元素的地址,值
    for (i = 0; i < N; i++)
        printf("%p: %d\n", &a[i], a[i]);
    printf("\n");
    //输出一维char数组b中每个元素的地址,值
    for (i = 0; i < N; i++)
        printf("%p: %c\n", &b[i], b[i]);
    printf("\n");
    //输出数组名a和b对应的值
    printf("a=%p\n", a);
    printf("b=%p\n", b);
    return 0;

}

int 型数组:连续存放 每个元素占四个字节

char 型数组:连续存放 每个元素占一个字节

数组名a对应的值与&a[0]一样,

 

task1_2.c

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 2
#define M 4
int main()
{
    int a[N][M] = { {1,9,8,4},{2,0,2,2}};
    char b[N][M] = { { '1','9','8','4' },{'2','0','2','2'} };


    int i,j;
    
    //输出二维数组a中每个元素的地址和值
    for (i = 0; i < N; i++)
        for(j=0;j<M;j++)
        printf("%p: %d\n", &a[i][j], a[i][j]);
    printf("\n");
    //输出二维char数组b中每个元素的地址,值
    for (i = 0; i < N; i++)
        for(j=0;j<M;j++)
        printf("%p: %c\n", &b[i][j] ,b[i][j]);
    printf("\n");


    return 0;

}

Int型二维数组:连续存放,每个元素占四个内存字节单元

char型二维数组:连续存放,每个元素占一个内存字节单元

 

实验任务2

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 
int days_of_year(int year, int month, int day);
int main()
{
    int year, month, day;
    int days;
    
    while (scanf("%d%d%d", &year, &month, &day) != EOF) {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);

    }
    return 0;

}
int days_of_year(int year, int month, int day)
{
    int days=0,l,m,n,i,j;
    int mon[13];
    
    for (i = 1; i < 13; i++) {
        if (i == 1 || i == 3 || i == 5 || i == 7 || i == 8 || i == 10 || i == 12)
            mon[i] = 31;
        if (i == 4 || i == 6 || i == 9 || i == 11)
            mon[i] = 30;
        if (year % 4 == 0 && year % 100 != 0) {
            if (i == 2)
                mon[i] = 29;
        }
        else
            if (i == 2)
                mon[i] = 28;
    }
    for (j = 1; j < month; j++)
        days += mon[j];
    days = days + day;
    return days;

}

 

实验任务3

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);
int main()
{
    int scores[N];
    double ave;
    printf("录入%d个分数:\n", N);
    input(scores, N);

    printf("\n输出课程数:\n");
    output(scores, N);

    printf("\n课程分数处理:计算均分、排序...\n");
    ave = average(scores, N);
    bubble_sort(scores, N);

    printf("\n输出课程均分:%.2f\n", ave);
    printf("\n输出课程分数(高-->低):\n");
    output(scores, N);

    return 0;
}
//函数定义
//输入n个整数保存到整型数组x中
void input(int x[], int n)
{
    int i;
    for (i = 0; i < n; i++)
        scanf("%d", &x[i]);
}
//输出整型数组x的的n个元素
void output(int x[], int n)
{
    int i;
    for (i = 0; i < n; i++)
        printf("%d ", x[i]);
    printf("\n");
}
//计算整型数组x中n个元素均值
double average(int x[], int n) {
    int i;
    double s = 0, average;
    for (i = 0; i < n; i++)
        s = s + x[i];
    average = s / n;
    return average;
}
//对数组n个元素进行冒泡排序
void bubble_sort(int x[], int n)
{
    int i, j, t;
    for (i = 0; i < n - 1; i++)
        for (j = 0; j < n - 1 - i; j++)
        {
            if (x[j] < x[j + 1])
            {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }
        }
}

 

实验任务4

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 100
void dec2n(int x, int n);//函数声明

int main()
{    
    int x;
    printf("输入一个十进制整数: ");
    while (scanf("%d", &x) != EOF)
    {
        dec2n(x, 2);
        dec2n(x, 8);
        dec2n(x, 16);

        printf("\n输入一个十进制整数:");

    }
    return 0;
}
void dec2n(int x, int n)
{
    int ans[N],i=0,j,t;
    char a[16] = { '0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F' };
    while (x!= 0)
    {
        t = x % n;
        ans[i] = t;
        x = x / n;
        i++;
    }
    for (j = 0; j <= i - 1; i--)
        printf("%c", a[ans[i-1]]);
    printf("\n");

}

 

实验任务5

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#define N 100
void func(int x[][N], int n);
void output(int x[][N], int n);

int main()
{
    int x[N][N];
    int i, j, n;
    printf("Enter n: ");
    while (scanf("%d", &n) != EOF)
    {
        func(x, n);
        output(x, n);
        printf("\nEnter n: ");
    }
    return 0;
}
void output(int x[][N], int n)
{
    int i, j;
    for (i = 0; i < n; i++) {
        for (j = 0; j < n; j++)
            printf("%5d",x[i][j]);

        printf("\n");
    }
}
void func(int x[][N], int n)
{
    int i, j;
    for (i = 0; i < n; i++)
    {
        for (j = 0; j <= i; j++)
            x[i][j] = j+1 ;
        for (; j > i && j < n; j++)
            x[i][j] = i + 1;
    }
}

 

实验任务六

task6_1.c

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 80
int main()
{
    char view1[N] = "hey,C,I have not love u yet.";
    char view2[N] = "hey,C,how can I love u?";
    char t[N];
    
    printf("交换前:\n");
    printf("view1:%s\n", view1);
    printf("view2:%s\n", view2);

    strcpy(t, view1);
    strcpy(view1, view2);
    strcpy(view2, t);

    printf("交换后:\n");
    printf("view1:%s\n", view1);
    printf("view2:%s\n", view2);

    return 0;
}

task6_2.c

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 80
int main()
{
    char view[2][N] = { "hey,C,I have not love u yet." , "hey,C,how can I love u ?"};
    char t[N];
    
    printf("交换前:\n");
    printf("view1:%s\n", view[0]);
    printf("view2:%s\n", view[1]);

    strcpy(t, view[0]);
    strcpy(view[0], view[1]);
    strcpy(view[1], t);

    printf("交换后:\n");
    printf("view1:%s\n", view[0]);
    printf("view2:%s\n", view[1]);

    return 0;
}

 

实验任务七

 

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 5
#define M 20
void bubble_sort(char str[][M], int n);

int main()
{
    char name[][M] = { "Bob","Bill","Joseph","Taylor","George" };
    int i;

    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);

    printf("\n排序中...\n");
    bubble_sort(name, N);

    printf("\n按字典输出名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);


    return 0;
}
void bubble_sort(char str[][M], int n)
{
    int i, j;
    char t[M];
    for(i=0;i<n-1;i++)
        for (j = 0; j < n - 1 - i; j++)
        {
            if (strcmp(str[j], str[j + 1]) > 0)
            {
                strcpy(t, str[j]);
                strcpy(str[j], str[j + 1]);
                strcpy(str[j + 1], t);
            }
        }


}

 

 

 

 

 
posted @ 2022-11-24 19:44  汤玉龙  阅读(16)  评论(0)    收藏  举报