mysql

 

1 insert into children values(8, "王刚", 20);

 

http://www.cnblogs.com/mr-wid/archive/2013/05/09/3068229.html

 

2 update数据

update children set fname = ‘Fony’ where age=8；

3 update 

int age=8;
char name[10]=Tomy;
char query_str[50]={0};
sprintf(query_str,"update children set fname '%s' where age=%d",name,age);
res=mysql_query(mysql_main,query_str);

4 int mysql_update(MYSQL *mysql_main，char query_str[])

{

 

}