数据结构算法练习1-循环双端队列

//double_queue.h
template <typename T>
class DoubleQueue
{
public:
    DoubleQueue(int size=10);
    ~DoubleQueue();
    void EnQueue(T item, int end);
    void DeQueue(int end);
    bool IsEmpty();
    bool IsFull();
    void List(int end);

private:
    T* data_;
    int end1_;
    int end2_;
    int size_;
};

template <typename T>
DoubleQueue<T>::DoubleQueue(int size/* =10 */)
    : size_(size)
    , end1_(0)
    , end2_(0)
{
    data_ = new T[size];
}

template <typename T>
DoubleQueue<T>::~DoubleQueue()
{
    delete [] data_;
}

template <typename T>
void DoubleQueue<T>::EnQueue(T item, int end)
{
    if (end == 1)
    {
        end1_ = (end1_ + 1) % size_;
        data_[end1_] = item;
    }
    else
    {
        data_[end2_] = item;
        end2_ = (end2_-1+size_)%size_;
    }
}

template <typename T>
void DoubleQueue<T>::DeQueue(int end)
{
    assert(!IsEmpty());
    if (end == 1)
    {
        end1_ = (end1_ - 1) % size_;
    }
    else
    {
        end2_ = (end2_ + 1 +size_) % size_;
    }
}

template <typename T>
bool DoubleQueue<T>::IsEmpty()
{
    return end1_ == end2_;
}

template <typename T>
bool DoubleQueue<T>::IsFull()
{
    return (end1_+1)%size_ == end2_;
}

template <typename T>
void DoubleQueue<T>::List(int end)
{
    if (end == 1)
    {
        for (int i=(end2_+1)%size_; i!=(end1_+1)%size_; i=(i+1)%size_)
        {
            cout<<data_[i]<<setw(3);
        }
    }
    else
    {
        for (int i=end1_; i!=(end2_+1)%size_; i=(i-1+size_)%size_)
        {
            cout<<data_[i]<<setw(3);
        }
    }
}

测试

int main()
{
    DoubleQueue<int> queue(5);
    queue.EnQueue(1, 1);
    queue.EnQueue(2, 1);
    queue.EnQueue(3, 1);
    queue.EnQueue(4, 1);
    queue.List(1);
    system("pause");
    return 0;
}

 

posted @ 2012-12-04 17:03  tszhao  阅读(156)  评论(0编辑  收藏  举报