PATA1035Password

  • 需要注意的就是把判定函数提取出来,这样可以简化代码,同时参数引用了&,可以对于传入参数进行修改。
    参考代码:
#define _CRT_SECURE_NO_WARNINGS
#include<cstdio>
#include<cstring>
#include<cstdlib>

struct node
{
	char name[20], password[20];
	bool ischange;//如果ischange==true表示password已经修改
}T[1005];

//函数用来判断t的password的是否需要修改,若需要则cnt加1
void crypt(node& t, int& cnt)
{
	int len = strlen(t.password);
	for (int i = 0; i < len; i++)
	{
		if (t.password[i] == '1')
		{
			t.password[i] = '@';
			t.ischange = true;
		}
		else if (t.password[i] == '0')
		{
			t.password[i] = '%';
			t.ischange = true;
		}
		else if (t.password[i] == 'l')
		{
			t.password[i] = 'L';
			t.ischange = true;
		}
		else if (t.password[i] == 'O')
		{
			t.password[i] = 'o';
			t.ischange = true;
		}
	}

	if (t.ischange)
	{
		cnt++;
	}
}

int main()
{
	int n, cnt = 0;
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		scanf("%s %s", T[i].name, T[i].password);
		T[i].ischange = false;
	}

	for (int i = 0; i < n; i++)
	{
		crypt(T[i], cnt);
	}
	if (cnt == 0)
	{
		if (n == 1)
		{
			printf("There is %d account and no account is modified", n);
		}
		else
		{
			printf("There are %d accounts and no account is modified", n);
		}
	}
	else
	{
		printf("%d\n", cnt);
		for (int i = 0; i < n; i++)
		{
			if (T[i].ischange == true)
			{
				printf("%s %s\n", T[i].name, T[i].password);
			}
		}
	}

	system("pause");
	return 0;
}

posted @ 2019-07-24 10:52  睿晞  阅读(159)  评论(0编辑  收藏  举报