随笔分类 -  规律

hdu 1005(规律)
摘要://循环节#include <cstdio>#include <iostream>using namespace std;int f[49];int main() { int i; f[1] = f[2] = 1; int a, b, n; while (scanf("%d%d%d", &a, &b, &n), a+b+n) { for (i=3; i<49; ++i) f[i] = (a * f[i-1] + b * f[i-2]) % 7; printf ("%d\n", f[n%48]); } 阅读全文
posted @ 2012-04-03 22:21 Try86 阅读(147) 评论(0) 推荐(0)