1 /*
2 * 题目要求:求三角形的最大面积
3 * 方法:凸包+枚举凸包上的点
4 */
5
6 #include <cmath>
7 #include <cstdio>
8 #include <cstdlib>
9 #include <iostream>
10
11 using namespace std;
12
13 const int N = 50005;
14 const double eps = 1e-8;
15
16 struct point {
17 int x;
18 int y;
19 }p[N], stack[N];
20
21 bool isZero(double x) {
22 return (x > 0 ? x : -x) < eps;
23 }
24
25 double dis(point A, point B) {
26 return sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));
27 }
28
29 int crossProd(point A, point B, point C) {
30 return (B.x-A.x)*(C.y-A.y) - (B.y-A.y)*(C.x-A.x);
31 }
32
33 int cmp(const void *a, const void *b) {
34 point *c = (point *)a;
35 point *d = (point *)b;
36 double k = crossProd(p[0], *c, *d);
37 if (k<eps || (isZero(k)&&dis(p[0], *c)>dis(p[0], *d))) return 1;
38 return -1;
39 }
40
41 int Graham(int n) {
42 int x = p[0].x;
43 int y = p[0].y;
44 int mi = 0;
45 for (int i=1; i<n; ++i) {
46 if (p[i].x<x || (p[i].x==x&&p[i].y<y)) {
47 x = p[i].x;
48 y = p[i].y;
49 mi = i;
50 }
51 }
52 point tmp = p[mi];
53 p[mi] = p[0];
54 p[0] = tmp;
55 qsort(p+1, n-1, sizeof(point), cmp);
56 p[n] = p[0];
57 for (int i=0; i<3; ++i) stack[i] = p[i];
58 int top = 2;
59 for (int i=3; i<n; ++i) {
60 while (crossProd(stack[top-1], stack[top], p[i])<=eps && top>=2) --top;
61 stack[++top] = p[i];
62 }
63 return top;
64 }
65
66 double maxTrangle(int n) {
67 int top = Graham(n);
68 double area, maxArea = 0;
69 for (int i=0; i<top; ++i) {
70 for (int j=i+1; j<top; ++j) {
71 for (int k=j+1; k<=top; ++k) {
72 area = crossProd(stack[i], stack[j], stack[k]);
73 if (maxArea < area) maxArea = area;
74 }
75 }
76 }
77 return maxArea * 0.5;
78 }
79
80 int main() {
81 int n;
82 while (scanf("%d", &n) != EOF) {
83 for (int i=0; i<n; ++i) scanf ("%d%d", &p[i].x, &p[i].y);
84 double ans = maxTrangle(n);
85 printf ("%.2lf\n", ans);
86 }
87 return 0;
88 }