/*
* 题目要求:求面积最大的那个面的编号
* 方法:分别求每个面的面积,并比较最大的面积
*/
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <iostream>
using namespace std;
const int N = 55;
struct point {
int x;
int y;
}p[N], sp[N];
double crossProd(point A, point B, point C) {
return (B.x-A.x)*(C.y-A.y) - (B.y-A.y)*(C.x-A.x);
}
int main() {
int t;
scanf ("%d", &t);
while (t--) {
int n;
scanf ("%d", &n);
for (int i=1; i<=n; ++i) scanf ("%d%d", &p[i].x, &p[i].y);
int m;
scanf ("%d", &m);
double maxArea = 0;
int ans = 0;
for (int j=1; j<=m; ++j) {
int cs, num;
scanf ("%d", &cs);
int k = 0;
for (int i=0; i<cs; ++i) {
scanf ("%d", &num);
sp[k++] = p[num];
}
double area = 0;
for (int i=2; i<k; ++i) area += crossProd(sp[0], sp[i-1], sp[i]);
if (maxArea < fabs(area)) {
maxArea = fabs(area);
ans = j;
}
}
printf ("%d\n", ans);
}
}