/*
Name: 最短路(bellmanFord)
Copyright:
Author: Try_86
Date: 12/04/12 12:42
Description: 对每个起始点运行一次bellmanFord,求最短路
*/
#include <cstdio>
#include <iostream>
using namespace std;
const int N = 1005;
const int M = 500500;
const int MAX = 1000000000;
int dis[N], ss[N], ds[N];
struct edge {
int u;
int v;
int w;
}e[M];
void init(int vs, int s) {
for (int i=1; i<=vs; ++i) dis[i] = MAX;
dis[s] = 0;
return ;
}
void relax(int u, int v, int w) {
if (dis[v] > dis[u] + w) dis[v] = dis[u] + w;
return ;
}
void bellmanFord(int es, int vs, int s) {
init(vs, s);
for (int i=1; i<vs; ++i) {
for (int j=0; j<es; ++j) relax(e[j].u, e[j].v, e[j].w);
}
return ;
}
int main() {
int t, s, d;
while (scanf("%d%d%d", &t, &s, &d) != EOF) {
int vs = 0;
for (int i=0; i<t; ++i) {
scanf ("%d%d%d", &e[i].u, &e[i].v, &e[i].w);
e[i+t].v = e[i].u;
e[i+t].u = e[i].v;
e[i+t].w = e[i].w;
if (vs < e[i].u) vs = e[i].u;
if (vs < e[i].v) vs = e[i].v;
}
for (int i=0; i<s; ++i) scanf ("%d", &ss[i]);
for (int i=0; i<d; ++i) scanf ("%d", &ds[i]);
int mins = MAX;
for (int i=0; i<s; ++i) {
bellmanFord(t<<1, vs, ss[i]);
for (int j=0; j<d; ++j) {
if (mins > dis[ds[j]]) mins = dis[ds[j]];
}
}
printf ("%d\n", mins);
}
return 0;
}