/*
* 最小生成树练手题,采用kruskal求解
*/
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
using namespace std;
const int M = 5050;
int p[M];
struct edge {//边节点
int a;
int b;
int w;
}e[M];
int cmp(const void *a, const void *b) {//按权值从小到大排序
return (*(edge *)a).w - (*(edge *)b).w;
}
void init(int vs) {//初始化集合
for (int i=1; i<=vs; ++i) p[i] = i;
return ;
}
int find(int v) {
if (p[v] != v) p[v] = find(p[v]);
return p[v];
}
int join(edge e) {
int x, y;
x = find(e.a);
y = find(e.b);
if (x != y) {
p[x] = y;
return e.w;
}
return 0;
}
int kruskal(int es, int vs) {
int ans = 0;
init(vs);
qsort(e, es, sizeof(edge), cmp);
for (int i=0; i<es; ++i) ans += join(e[i]);
return ans;
}
int main() {
int vs;
while (scanf("%d", &vs), vs) {
int es = vs * (vs - 1) / 2;
for (int i=0; i<es; ++i) scanf("%d%d%d", &e[i].a, &e[i].b, &e[i].w);
int ans = kruskal(es, vs);
printf ("%d\n", ans);
}
return 0;
}