/*
* hash+数学,很好的题
* 对整数求hash,采用除余法,及线性探测解决冲突
* 注意:devc++中不能定义全局变量count,它和库函数中的函数名同名了
*/
#include <cstdio>
#include <cstring>
#include <iostream>
using namespace std;
const int M = 175447;
int counts[M];
int result[M];
int temp[101];
int hashInt(int s) {
int k = s % M;
if (k < 0) k += M;
while (counts[k] && result[k]!=s) k = (k + 1) % M;
return k;
}
int solve(int a, int b, int c, int d) {
if (a>0&&b>0&&c>0&&d>0 || a<0&&b<0&&c<0&&d<0) return 0;
memset(counts, 0, sizeof(counts));
int s, p, i, j;
for (i=1; i<101; ++i) {
for (j=1; j<101; ++j) {
s = a * temp[i] + b * temp[j];
p = hashInt(s);
result[p] = s;
++counts[p];
}
}
int ans = 0;
for (i=1; i<101; ++i) {
for (j=1; j<101; ++j) {
s = -(c * temp[i] + d * temp[j]);
p = hashInt(s);
ans += counts[p];
}
}
return ans;
}
int main() {
int a, b, c, d;
for (int i=1; i<101; ++i) temp[i] = i * i;
while (scanf("%d%d%d%d", &a, &b, &c, &d) != EOF) {
int ans = solve(a, b, c, d);
printf ("%d\n", ans<<4);
}
return 0;
}