jsp 跳转

1、使用form表单 action对象可以是jsp、servlet 点击 submit后 地址改变 页面跳转

 <FORM name="LoginForm" action="tr" method="GET">
	  name: <input type="text" name="nu1" /> <br /><br />
	  password: <input type="password" name="nu2" /><br /><br />
	  <input type="submit" value="Submit" />
 </FORM>

或者：

<FORM name="LoginForm" action="tr" method="GET">
      name: <input type="text" name="nu1" /> <br /><br />
      password: <input type="password" name="nu2" /><br /><br />
      <input type="button" onclick="check()" value="submit" /> 
</FORM>

<script type="text/javascript">
function check(){
document.LoginForm.submit();
}
</script>

相应的servlet：

  <servlet>
    <servlet-name>tr</servlet-name>
    <servlet-class>tr</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>tr</servlet-name>
    <url-pattern>/tr</url-pattern>
  </servlet-mapping>	

 源程序：

	public void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {

		response.setContentType("text/html");
		String uname = request.getParameter("nu1");	
		String upassword = request.getParameter("nu2");  
		PrintWriter ou = response.getWriter();
	        ou.println("userddd:     "+uname+"<br>");
		ou.println("passdddword:     "+upassword+"<br>");	

	}