dp &单调队列优化
这个题 : k<=i, 决策点k 可以等于i ,所以在 i 入队后递推
#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
const int N =503,M =1e4+2;
#define int long long
int n,m,E,X[N],F[N],C[N],f[N][M];
int q[N],hh,tt;
struct T{
int C,F,x;
}a[N];
int cmp(T &a,T &b){ return a.x<b.x; }
int func(int i,int k){
return f[i - 1][k]-C[i]*k + k*k*(X[i]-X[i-1]);
}
signed main(){
cin>>m>>E>>n;
int i,j;
for(i=1;i<=n;i++) cin>>a[i].x>>a[i].F>>a[i].C;
sort(a+1,a+1+n,cmp);
for(i=1;i<=n;i++) X[i]=a[i].x,F[i]=a[i].F,C[i]=a[i].C;
memset(f,0x3f,sizeof f);
for(i=0;i<=n;i++) f[i][0]=0;
for(i=1;i<=n;i++){
hh=1,tt=0; q[++tt]=0;
for(j=1;j<=m;j++){
while(hh<=tt&&q[hh]<j-min(F[i],j)) hh++;
while(hh<=tt&&func(i,j)<=func(i,q[tt])) tt--;
q[++tt]=j ;
int k=q[hh];
f[i][j]= func(i,k)+C[i]*j;
}
}
int ans=f[n][m]+ m*m*(E-X[n]);
cout<<ans;
}
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