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$\sum \frac{1}{n^2}$

 

$\sum \frac{1}{n^2}$

 

 

\begin{equation}\label{equation 1} st_i = \{     \begin{array}{ll}         d_i, \quad 2(d_i - d_{i - 1})  > tx_{i - 1} + g; &   \\         d_i + tx_{i - 1} + g - 2(d_i - d_{i - 1}), & otherwise.     \end{array} \end{equation}



\begin{equation}\label{equation 1} st_i = \{     \begin{array}{ll}         d_i, \quad 2(d_i - d_{i - 1})  > tx_{i - 1} + g; &   \\         d_i + tx_{i - 1} + g - 2(d_i - d_{i - 1}), & otherwise.     \end{array} \end{equation}
posted on 2015-03-14 11:40  Duang!Duang!  阅读(81)  评论(2)    收藏  举报