js会把相同的方法名给覆盖了，很多时候我们都无法再页面加载的时候写多个onload事件，这样只有最后一个才能起效，所以从网上找了找，最后决定自己写一个，例子很简单，希望有高人来指导指导
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>javascript_window.ready</title>
</head>
<body>
<script type="text/javascript">
(function(w){
w.readyLength=0;
w.readyFunction=[];
w.ready=function(load){
w.readyFunction[w.readyLength]=load;
w.readyLength++;
}
w.init=function(){
clearInterval(w.readyById);
w.readyFunction.reverse();
while(w.readyFunction.length-1>=0){
w.readyFunction[w.readyFunction.length-1]();
w.readyFunction.pop();
w.readyLength--;
}
}
if('onreadystatechange' in w.document){
w.document.onreadystatechange=onreadystatechange;
}else{
w.readyById = setInterval(onreadystatechange,10);
}
function onreadystatechange(){
console.log(w.document.readyState)
if(w.document.readyState == "complete"){
setTimeout(init,1);
}else if(w.document.addEventListener){
w.document.addEventListener( "DOMContentLoaded", init, false );
w.addEventListener('load',init,false)
}else{
document.attachEvent( "onreadystatechange", init );
w.attachEvent('onload',init)
}
}
}(this));
(function(){
window.ready(function(){
console.log('ready1')
});
window.ready(function(){
console.log('ready2')
})
window.ready(function(){
console.log('ready3')
})
}());;;
</script>
</body>
</html>
