【LeetCode从零单排】No.135Candy(双向动态规划)
2017-07-16 18:35 tlnshuju 阅读(216) 评论(0) 收藏 举报1.题目
There are N children standing in a line. Each child is assigned a rating value.
You are giving candies to these children subjected to the following requirements:
- Each child must have at least one candy.
- Children with a higher rating get more candies than their neighbors.
What is the minimum candies you must give?
2.代码
public class Solution {
   	public int candy(int[] ratings){
		int size=ratings.length;
		if(size<=1) return size;
		int[] nums=new int[size];
		for(int i=0;i<size;i++){
             nums[i]=1;
		}
		for(int j=1;j<size;j++){
			if(ratings[j]>ratings[j-1]) nums[j]=nums[j-1]+1;
		}
		for(int m=size-1;m>0;m--){
			if(ratings[m-1]>ratings[m]){
				nums[m-1]=Math.max(nums[m]+1,nums[m-1]);
			}
		}
		int result=0;
		for(int n=0;n<size;n++){
			result+=nums[n];
		}
		
		return result;
   	}
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