微信抢红包的简单实现

前言

  群里都在玩抢红包,抢了再发,发了再抢,简直是无聊,程序员感兴趣是的如何实现,这里简单说说实现思路,附上dome,代码有点low,好在是实现了,感兴趣的园友可以完善下,觉得还行的可以点个赞

正文

  直接进入主题,先附上几张效果图(缺陷)

  

  ====================100块发30个红包============================

  

  ====================50块发13个红包============================

  

  ====================1块发10个红包============================

  

  =========================================================

  发红包需要满足以下几个条件

  1.总金额不变

  2.每个红包都必须有钱

  3.尽量的均匀点,不然抢红包没什么意思了

  =========================================================

  实现思路

  1.首先要确定最小单位,这里是精确到分,我这里以int类型进行计算,得出的结果也全是int类型

  2.数据均匀,这里以  1<n<(剩余金额/剩余红包数)*2,这里防止一个红包抢走大量的钱,这里需要写个递归,去检查数据值是否过大,50元发13个红包的第3图,就是因为没有检查数据,导致钱不平均,这个可以根据自己的玩法去设置.

  3.余数处理,当数据平均给20个红包,肯定跟总金额有所偏差,这时候我们就要多退少补,如果大于总金额,让红包金额多的去减少(总金额/总人数),如果还有剩余,就让第二多的去减少,直到补完这个空缺为止,反之亦然.

  4.打乱顺序,细心的园友可能发现,红包是有顺序规律的,我们必须简单的写个function去打乱它.  

  =========================================================

  demo

  

/// <summary>
        /// 抢红包
        /// </summary>
        /// <param name="money"></param>
        /// <param name="num"></param>
        /// <returns></returns>
        public List<int> qhb(int money, int num)
        {
            int min = 1;
            int pjs = money / num;
            List<int> list = new List<int>();
            Random rnd = new Random();
            for (int i = 0; i < num; i++)
            {
                int max = (money / (num - i)) * 2;
                int s = rnd.Next(min, max);
                s = checkmoney(s, min, max);
                list.Add(s);
                money -= s;
            }
            //前面数据都是合理的,结尾必须多退少补
            list = checklist(money, pjs, list);
            return list;
        }
View Code

 

 1 /// <summary>
 2         /// 获取到合理数据
 3         /// </summary>
 4         /// <param name="i"></param>
 5         /// <param name="min"></param>
 6         /// <param name="max"></param>
 7         /// <returns></returns>
 8         public int checkmoney(int i, int min, int max)
 9         {
10             if (i > max || i < min)
11             {
12                 Random rnd = new Random();
13                 i = rnd.Next(min, max);
14                 return checkmoney(i, min, max);
15             }
16             return i;
17         }
View Code

 

 1 /// <summary>
 2         /// 余数处理
 3         /// </summary>
 4         /// <param name="money"></param>
 5         /// <param name="list"></param>
 6         /// <returns></returns>
 7         public List<int> checklist(int money, int pjs, List<int> list)
 8         {
 9             if (money != 0)
10             {
11                 if (money > 0)
12                 {
13 
14                     List<int> list_order = maopao(list);
15                     //给最小
16                     if (money / pjs == 0)
17                     {                      
18                         list_order[0] += money;
19                     }
20                     else
21                     {
22                         for (int i = 0; i < money / pjs + 1; i++)
23                         {
24                             if (i == money / pjs)
25                             {
26                                 list_order[i] += (money - (money / pjs) * pjs);
27                             }
28                             else
29                             {
30                                 list_order[i] += pjs;
31                             }
32 
33                         }
34                     }
35                     return list_order;
36                 }
37                 else
38                 {
39 
40                     List<int> list_order = maopao(list,"desc");
41                     //给最大
42                     if (money / pjs == 0)
43                     {
44 
45                         list_order[0] += money;
46                     }
47                     else
48                     {
49                         for (int i = 0; i < -(money / pjs) + 1; i++)
50                         {
51                             if (i == -(money / pjs))
52                             {
53                                 list_order[i] += (money - (money / pjs) * pjs);
54                             }
55                             else
56                             {
57                                 list_order[i] -= pjs;
58                             }
59 
60                         }
61                     }
62                     return list_order;
63                 }
64             }
65             return list;
66         }
View Code

 

 1  /// <summary>
 2         /// 冒泡排序
 3         /// </summary>
 4         /// <param name="list"></param>
 5         /// <param name="order"></param>
 6         /// <returns></returns>
 7         public List<int> maopao(List<int> list,string order = "asc")
 8         {
 9             if (order != "asc")
10             {
11                 for (int i = 0; i < list.Count; i++)
12                 {
13                     for (int j = 0; j < list.Count - i - 1; j++)
14                     {
15                         if (list[j + 1] > list[j])
16                         {
17                             int temp = list[j];
18                             list[j] = list[j + 1];
19                             list[j + 1] = temp;
20 
21                         }
22                     }
23                 }
24             }
25             else 
26             {
27                 for (int i = 0; i < list.Count; i++)
28                 {
29                     for (int j = 0; j < list.Count-i-1;j++)
30                     {
31                         if (list[j+1] < list[j])
32                         {
33                             int temp = list[j];
34                             list[j] = list[j+1];
35                             list[j+1] = temp;
36 
37                         }
38                     }
39                 }
40             }
41             return list;
42         }
View Code

 

 1 /// <summary>
 2         /// 打乱顺序
 3         /// </summary>
 4         /// <param name="list"></param>
 5         /// <returns></returns>
 6         public List<int> suiji(List<int> list) 
 7         {
 8             Random rnd = new Random();
 9             for (int i = 0; i < list.Count; i++)
10             {
11                 int temp = list[i];
12                 int j = rnd.Next(0, list.Count-1);
13                 list[i] = list[j];
14                 list[j] = temp;
15             }
16             return list;
17         }
View Code

 

posted @ 2016-07-07 15:22  提伯斯  阅读(4958)  评论(2编辑  收藏  举报