python 元组(tuple)

python中的元组和list类似，但是tuple不可以改变其中元素的值。

# 创建元祖
tuple1 = 1, 2
print(tuple1)
print(tuple1[0])
tuple1_ = 1, 2 , 18+6.6j
print(tuple1_)

tuple2tuple = tuple((1,))  # 参数需要iterable
print('tuple2tuple', tuple1_)
list2tuple = tuple([1, 2, 3])  # 将列表转换为元祖
print('list2tuple', list2tuple)
dic2tuple = tuple({'a':1, 'b':2})  # 字典转换为元素默认将其key值转换为元祖
print('dic2tuple', dic2tuple)

# 查找元素中的最大值 最小值
tuple_max = max((1, 2, -1, 1e10))
print('tuple max:', tuple_max)
tuple_min = min((1, 2, -1, 1e10))
print('tuple min:', tuple_min)
tuple_max2 = max(('a', 'b', 'd'))
print(tuple_max2)

# 与list不同，tuple的元素值不可以改变
tuple1 = 2, 3
print(tuple1)
# 以下修改元祖元素的操作是非法的
# tuple1[0] = 1

# 访问元祖
# tuple可以索引，切片
tuple2 = (3,)
tuple3 = tuple1 + tuple2
print(tuple3[1:3])

# 元祖运算
# len()获得元祖的长度
print(len(tuple3))
# 元祖的复制
tuple4 = ('techi','yurina') * 5
print(tuple4)
# 成员运算符，元祖的元素是否存在
print('techi' in tuple4)
# 元祖的迭代
i = 0
for v in tuple4:
    i += 1
    print(i, v)

(1, 2)
1
(1, 2, (18+6.6j))
tuple2tuple (1, 2, (18+6.6j))
list2tuple (1, 2, 3)
dic2tuple ('a', 'b')
tuple max: 10000000000.0
tuple min: -1
d
(2, 3)
(3, 3)
3
('techi', 'yurina', 'techi', 'yurina', 'techi', 'yurina', 'techi', 'yurina', 'techi', 'yurina')
True
1 techi
2 yurina
3 techi
4 yurina
5 techi
6 yurina
7 techi
8 yurina
9 techi
10 yurina