matlab习题 —— 符号运算相关练习

matlab系列文章：👉 目录 👈

文章目录

• • 一、题目
  • • 1. 计算下列极限
    • 2. 计算下列导数
    • 3. 计算下列定积分
    • 4. 计算下列级数的和
  • 二、解答
  • • 题一，计算下列极限
    • • ①
      • ②
      • ③
      • ④
    • 题二，计算下列导数
    • • ①
      • ②
      • ③
      • ④
    • 题三，计算下列定积分
    • • ①
      • ②
      • ③
    • 题四，计算下列级数的和
    • • ①
      • ②
      • ③

一、题目

1. 计算下列极限

• (1) $$\underset{x\to 0}{\lim }\frac{\sqrt{1+x}-\sqrt{1-x}}{\sqrt[3]{1+x}-\sqrt[3]{1-x}}$$
• (2) $$\underset{x\to 0}{\lim }(\frac{3x+2}{3x-1}{)}^{2x-1}$$
• (3) $$\underset{x\to 0}{\lim }(\frac{1}{x^2}-\frac{1}{{\sin }^{2}x})$$
• (4) $$\underset{x\to 0}{\lim }(\frac{\pi }{2}-\arctan x{)}^{\frac{1}{\ln x}}$$

2. 计算下列导数

• (1) 求 $y^{{}^{\prime }}$,$$y=(\sqrt{x}+1)\arctan x$$
• (2) 求 $y^{{}^{\prime \prime }}$，$$y=\frac{1+x^2}{\sin x+\cos x}$$
• (3) 求 $y^{{}^{\prime }}$,$$y=\sqrt{x+\sqrt{x+\sqrt{x}}}$$
• (4) $$\{\begin{array}{rl}x& =a(\cos t+t\sin t)\\ y& =a(\sin t-t\cos t)\end{array}$$

3. 计算下列定积分

• (1) $${\int }_0^{\frac{\pi }{2}}\frac{\cos x}{1+{\sin }^{2}x}dx$$
• (2) $${\int }_0^a{x}^2\sqrt{\frac{a-x}{a+x}}dx$$
• (3) $${\int }_0^1\frac{dx}{(x^2-x+1{)}^{\frac{3}{2}}}$$

4. 计算下列级数的和

• (1) $$\sum _{n=1}^{\infty }\frac{1}{n^2}$$
• (2) $$\sum _{n=1}^{\infty }\frac{(-1{)}^{n-1}}{n}$$
• (3) $$\sum _{n=1}^{\infty }\frac{x^{2n-1}}{2n-1}$$

二、解答

题一，计算下列极限

①

>> syms x
>> y = ((1+x)^(1/2)-(1-x)^(1/2))/((1+x)^(1/3)-(1-x)^(1/3))
 
y =
 
((x + 1)^(1/2) - (1 - x)^(1/2))/((x + 1)^(1/3) - (1 - x)^(1/3))
 
>> limit(y,x,0)
 
ans =
 
3/2

②

>> syms x
>> y = ((3*x+2)/(3*x-1))^(2*x-1)
 
y =
 
((3*x + 2)/(3*x - 1))^(2*x - 1)
 
>> limit(y,x,0)
 
ans =
 
-1/2

③

>> syms x
>> y = ((1/x^2)-1/(sin(x)^2))
 
y =
 
1/x^2 - 1/sin(x)^2
 
>> limit(y,x,0)
 
ans =
 
-1/3

④

>> syms x
>> y = (pi/2 - atan(x))^(1/(log(x)))
 
y =
 
(pi/2 - atan(x))^(1/log(x))
 
>> limit(y,x,0)
 
ans =
 
1

题二，计算下列导数

①

>> y = (x^(1/2)+1)*atan(x)
 
y =
 
atan(x)*(x^(1/2) + 1)
 
>> diff(y,x)
 
ans =
 
atan(x)/(2*x^(1/2)) + (x^(1/2) + 1)/(x^2 + 1)

②

>> y = (1+x^2)/(sin(x)+cos(x))
 
y =
 
(x^2 + 1)/(cos(x) + sin(x))
 
>> y1 = diff(y,x)
 
y1 =
 
(2*x)/(cos(x) + sin(x)) - ((x^2 + 1)*(cos(x) - sin(x)))/(cos(x) + sin(x))^2
 
>> y2 = diff(y1,x)
 
y2 =
 
(x^2 + 1)/(cos(x) + sin(x)) + 2/(cos(x) + sin(x)) + (2*(x^2 + 1)*(cos(x) - sin(x))^2)/(cos(x) + sin(x))^3 - (4*x*(cos(x) - sin(x)))/(cos(x) + sin(x))^2

③

>> y = (x+(x+(x)^(1/2))^(1/2))^(1/2)
 
y =
 
(x + (x + x^(1/2))^(1/2))^(1/2)
 
>> diff(y,x)
 
ans =
 
((1/(2*x^(1/2)) + 1)/(2*(x + x^(1/2))^(1/2)) + 1)/(2*(x + (x + x^(1/2))^(1/2))^(1/2))

④

>> syms x y t a
>> x = a*(cos(t)+t*sin(t))
 
x =
 
a*(cos(t) + t*sin(t))
 
>> y = a*(sin(t)-t*cos(t))
 
y =
 
a*(sin(t) - t*cos(t))

>> dx = diff(x,t)
 
dx =
 
a*t*cos(t)
 
>> dy = diff(y,t)
 
dy =
 
a*t*sin(t)
 
>> dy/dx
 
ans =
 
sin(t)/cos(t)

题三，计算下列定积分

①

>> syms x y
>>  y = cos(x)/(1+(sin(x))^2)
 
y =
 
cos(x)/(sin(x)^2 + 1)
 
>> int(y,x,0,pi/2)
 
ans =
 
pi/4

②

>> syms x y a
>> y = (x^2)*((a-x)/(a+x))^(1/2)
 
y =
 
x^2*((a - x)/(a + x))^(1/2)
 
>> int(0,a)
 
ans =
 
0
 
>> int(y,x,0,a)
 
ans =
 
(a^3*(3*pi - 8))/12

③

>> syms x y a
>> y = 1/((x^2-x+1)^(3/2))
 
y =
 
1/(x^2 - x + 1)^(3/2)
 
>> int(y,x,0,1)
 
ans =
 
4/3

题四，计算下列级数的和

①

>> syms x y n
>> y = 1/(n^2)
 
y =
 
1/n^2
 
>> symsum(y,n,1,Inf)
 
ans =
 
pi^2/6

②

>> y = (-1)^(n-1)/n
 
y =
 
(-1)^(n - 1)/n
 
>> symsum(y,n,1,Inf)
 
ans =
 
log(2)

③

>> y = (x^(2*n-1))/(2*n-1)
 
y =
 
x^(2*n - 1)/(2*n - 1)
 
>> symsum(y,n,1,Inf)
 
ans =
 
piecewise(abs(x) < 1, atanh(x))