WpfApp_GridContextMenu

<Window x:Class="WpfApp_GridContextMenu.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="350" Width="525" Loaded="Window_Loaded">
    <Grid>
        <DataGrid AutoGenerateColumns="False" Height="208" HorizontalAlignment="Left" Margin="79,50,0,0" Name="dataGrid1" VerticalAlignment="Top" Width="319" ContextMenuOpening="dataGrid1_ContextMenuOpening">
            <DataGrid.ContextMenu>
                <ContextMenu>
                    <MenuItem Header="aaaaa" x:Name="m1"/>
                    <MenuItem Header="bbb" x:Name="m2"/>
                </ContextMenu>
            </DataGrid.ContextMenu>
            <DataGrid.Columns>
                <DataGridTextColumn Header="ID" Binding="{Binding Path=ID}"/>
                <DataGridTextColumn Header="Name" Binding="{Binding Path=Name}"/>
                <DataGridTextColumn Header="Status" Binding="{Binding Path=Status}"/>
            </DataGrid.Columns>
        </DataGrid>
    </Grid>
</Window>
 
 
 
private void dataGrid1_ContextMenuOpening(object sender, ContextMenuEventArgs e)
{
    if (e.OriginalSource is ScrollViewer)
    {
        e.Handled = true;
    }
    Person p = this.dataGrid1.SelectedItem as Person;
    if (p != null)
    {
        e.Handled = false;
        m1.IsEnabled = p.Status == 1; 
    }
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
    _lst.Add(new Person { ID = 1, Name = "1", Status = 1 });
    _lst.Add(new Person { ID = 2, Name = "2", Status = 2 });
    _lst.Add(new Person { ID = 3, Name = "3", Status = 3 });
    this.dataGrid1.ItemsSource = _lst;
}
private ObservableCollection<Person> _lst = new ObservableCollection<Person>();




posted @ 2013-04-10 12:15  队长  阅读(350)  评论(0编辑  收藏  举报