判断是原型属性还是实例属性
《Javascript高级程序设计》P152
function hasPrototypeProperty (object, name) {
return !object.hasOwnProperty(name) && (name in object)
}
如果是原型的属性那么返回true,如果是实例的属性则返回false
function hasPrototypeProperty (object, name) {
return !object.hasOwnProperty(name) && (name in object)
}
如果是原型的属性那么返回true,如果是实例的属性则返回false