素数筛选高效算法

用普通的筛法,1000 0000 的数,需要用时1600ms左右。

#include <stdio.h>
#include
<string.h>
#include
<math.h>

char dp[10000010];

const int inf = 10000001;
int t = sqrt(inf);

inline
void prime ( )
{
int i, j, k = 0,p;
dp[
1] = -1;
for (i = 2; i <= t; i++)
if( dp[i] != -1)
{
//p = inf / i;
for (j = 2; j <= inf / i ; j ++)
dp[i
* j] = -1;
}
}

int main( )
{
int N, k, i;
prime ( );
while(scanf("%d", &N) != EOF)
{


for (i =2; i < N; i++)
if (dp[i]!= -1)
printf(
"%d\n",i);
}
return 0;
}

而用如下筛法,则只需440ms左右。强大啊,也只需要开500 0000的数组。偶数不用筛了,筛过的也不用筛了。(thanks  tao  -_-) .

#include <stdio.h>
#include
<string.h>
#include
<math.h>

int dp[5000010] = {0};

int main( )
{
int N,i, j, k, n;
while (scanf("%d", &N) != EOF ) {
n
= sqrt( N +1);
for ( i = 3;i <= n; i += 2) {
if (dp[i >> 1])
continue;
int x = i << 1;
for( j = i * i; j <= N; j += x)
dp[j
>> 1] = 1;
}
printf(
"2\n");
int t = (N +1) / 2;
for ( i = 1; i < t ; i++) {
if(dp[i])
continue;
printf(
"%d\n",(i << 1 )+ 1);
}
}
return 0;

}

posted on 2011-07-21 22:11  more think, more gains  阅读(261)  评论(0)    收藏  举报

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