实验4 数组应用编程

#include <stdio.h>
#define N 4
int main() {
    int a[N] = { 1, 9, 8, 4 };
    char b[N] = { '1', '9', '8', '4' };
    int i;
    printf("sizeof(int) = %d\n", sizeof(int));
    printf("sizeof(char) = %d\n", sizeof(char));
    printf("\n");
    // 输出一维int数组a中每个元素的地址、值
    for (i = 0; i < N; ++i)
        printf("%p: %d\n", &a[i], a[i]);
    printf("\n");
    // 输出一维char数组b中每个元素的地址、值
    for (i = 0; i < N; ++i)
        printf("%p: %c\n", &b[i], b[i]);
    printf("\n");
    // 输出数组名a和b对应的值
    printf("a = %p\n", a);
    printf("b = %p\n", b);
    return 0;
}
//a连续,4个
//b连续,1个
//一样

#include <stdio.h>
#define N 2
#define M 4
int main() {
    int a[N][M] = { {1, 9, 8, 4}, {2, 0, 2, 2} };
    char b[N][M] = { {'1', '9', '8', '4'}, {'2', '0', '2', '2'} };
    int i, j;
    // 输出二维数组a中每个元素的地址和值
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %d\n", &a[i][j], a[i][j]);
    printf("\n");
    // 输出二维数组a中每个元素的地址和值
    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %c\n", &b[i][j], b[i][j]);
    return 0;
}
//是,4
//是,1

#include <stdio.h>
#define N 13
int days_of_year(int year, int month, int day);
int main() {
    int year, month, day;
    int days;
    while (scanf_s("%d%d%d", &year, &month, &day) != EOF) {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days);
    }
    return 0;
}
int days_of_year(int year, int month, int day)
{
    int a[13]; a[0] = 0;
    int i;
    for (i = 1; i <= 12; i++)
    {
        if (i == 1 || i == 3 || i == 5|| i == 7  || i == 8 || i == 10 || i == 12)
            a[i] = 31;
        else if (i == 4 || i == 6 || i == 9|| i == 11)
            a[i] = 30;
        else if (i == 2)
        {
            if ((year / 4) == 0 && (year / 100 )!= 0)
                a[i] = 29;
            else if ((year / 400) == 0)
                a[i] = 29;
            else
                a[i] = 28;
        }
    }
    
    int s=0;
    int j;
    for (j = 0; j < month; j++)
        s = s + a[j];
    s = s + day;
    return s;
}

#include <stdio.h>
#define N 5
// 函数声明
void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void bubble_sort(int x[], int n);
int main() {
    int scores[N];
    double ave;
    printf("录入%d个分数:\n", N);
    input(scores, N);
    printf("\n输出课程分数: \n");
    output(scores, N);
    printf("\n课程分数处理: 计算均分、排序...\n");
    ave = average(scores, N);
    bubble_sort(scores, N);
    printf("\n输出课程均分: %.2f\n", ave);
    printf("\n输出课程分数(高->低):\n");
    output(scores, N);
    return 0;
}
// 函数定义
// 输入n个整数保存到整型数组x中
void input(int x[], int n) {
    int i;
    for (i = 0; i < n; ++i)
        scanf_s("%d", &x[i]);
}
// 输出整型数组x中n个元素
void output(int x[], int n) {
    int i;
    for (i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}
double average(int x[], int n)
{
    int i;
    double s=0;
    for (i = 0; i < n; i++)
        s = s + x[i];
    double t;
    t = s / n;
    return t;
}
void bubble_sort(int x[], int n)
{
    int t,i,j;
    for(j=0;j<n-1;j++)
        for(i=0;i<n-j-1;i++)
            if (x[i] < x[i + 1])
            {
                t = x[i];
                x[i] = x[i + 1];
                x[i + 1] = t;
            }
    for(i=0;i<n;i++)
        printf("%d",x[i]);
}

#include <stdio.h>
#define N 100
void dec2n(int x, int n); // 函数声明
int main() {
    int x;
    printf("输入一个十进制整数: ");
    while (scanf_s("%d", &x) != EOF) {
        dec2n(x, 2); // 函数调用: 把x转换成二进制输出
        dec2n(x, 8); // 函数调用: 把x转换成八进制输出
        dec2n(x, 16); // 函数调用: 把x转换成十六进制输出
        printf("\n输入一个十进制整数: ");
    }
    return 0;
}
void dec2n(int x, int n)
{
    if (n == 2) {
        int a[100];
        int i, z = 0, c, count = 0;
        for (i = 0; x != 0; i++)
        {
            a[i] = x % 2;
            x= x / 2;
            count++;

        }
        for (c = count - 1; c >= 0; c--)
        {
            z = z * 10 + a[c];
        }
        printf("%d",z);
        printf("\n");
    }
    else if (n == 8)
    {
        int a[100];
        int i, z = 0, c, count = 0;
        for (i = 0; x != 0; i++)
        {
            a[i] = x % 8;
            x = x / 8;
            count++;

        }
        for (c = count - 1; c >= 0; c--)
        {
            z = z * 10 + a[c];
        }
        printf("%d\n", z);
    }
    else if (n == 16)
    {
        int a[100];
        int t;
        int i, z = 0, c, count = 0;
        for (i = 0; x != 0; i++)
        {
            if ((x % 16) <= 9)
            {
                t = x % 16 + 48;
                    a[i] = t;
            }
            else
            {
                t = x % 16 + 55;
                a[i] = t;
            }
            
            x = x / 16;
            count++;

        }
        for (c = count - 1; c >= 0; c--)
        {
             printf("%c",a[c] );
        }
        
    }
}

#include <stdio.h>
#define N 100
// 函数声明
void func(int x[][N], int n); // 注意:两维数组作为形参的语法
void output(int x[][N], int n); // 注意:两维数组作为形参的语法
int main() {
    int x[N][N];
    int i, j, n;
    printf("Enter n: ");
    while (scanf_s("%d", &n) != EOF) {
        func(x, n); // 注意:两维数组作为实参的语法
        output(x, n); // 注意:两维数组作为实参的语法
        printf("\nEnter n: ");
    }
    return 0;
}
// 函数定义
// 功能:输出两维数组x中的数据,数据项n行、n列
void output(int x[][N], int n) {
    int i, j;
    for (i = 0; i < n; ++i) {
        for (j = 0; j < n; ++j)
            printf("%5d", x[i][j]);
        printf("\n");
    }
}
void func(int x[][N], int n)
{
    int i, j;
    for (i = 0; i < n; i++)
        for (j = 0; j < n; j++)
            if (i >= j)
                x[i][j] = j + 1;
            else
                x[i][j] = i + 1;
}

#include <stdio.h>
#include <string.h>
#define N 80
int main() {
    char views1[N] = "hey, C, I have not love u yet.";
    char views2[N] = "hey, C, how can I love u?";
    char t[N];
    printf("交换前: \n");
    printf("views1: %s\n", views1);
    printf("views2: %s\n", views2);
    // 交换
    strcpy_s(t, views1);
    strcpy_s(views1, views2);
    strcpy_s(views2, t);
    printf("交换后: \n");
    printf("views1: %s\n", views1);
    printf("views2: %s\n", views2);
    return 0;
}

#include <stdio.h>
#include <string.h>
#define N 80
int main() {
    char views[2][N] = { "hey, C, I have not love u yet.",
        "hey, C, how can I love u?" };
    char t[N];
    printf("交换前: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);
    // 交换
    strcpy_s(t, views[0]);
    strcpy_s(views[0], views[1]);
    strcpy_s(views[1], t);
    printf("交换后: \n");
    printf("views1: %s\n", views[0]);
    printf("views2: %s\n", views[1]);
    return 0;
}

#include <stdio.h>
#include <string.h>
#define N 5
#define M 20
void bubble_sort(char str[][M], int n); // 函数声明
int main() {
    char name[][M] = { "Bob", "Bill", "Joseph", "Taylor", "George" };
    int i;
    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    printf("\n排序中...\n");
    bubble_sort(name, N); // 函数调用
    printf("\n按字典序输出名单:\n");
    for (i = 0; i < N; i++)
        printf("%s\n", name[i]);
    return 0;
}
void bubble_sort(char str[][M], int n)
{
    int i, j;
    char t[100];
    for (j = 0; j < n - 1; j++)
        for (i = 0; i < n - j - 1; i++)
            if (strcmp(str[i], str[i + 1]) > 0)
            {
                strcpy_s(t,str[i]);
                strcpy_s(str[i], str[i+1]);
                strcpy_s(str[i+1], t);
            }
}

 

posted @ 2022-11-23 17:30  殷正阳  阅读(16)  评论(0)    收藏  举报