实验3 C语言控制语句应用编程

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80
void print_text(int line, int col, char text[]); // 函数声明
void print_spaces(int n); // 函数声明
void print_blank_lines(int n); // 函数声明
int main() {
    int line, col, i;
    char text[N] = "hi, November~";
    srand(time(0)); // 以当前系统时间作为随机种子
    for (i = 1; i <= 10; ++i) {
        line = rand() % 25;
        col = rand() % 80;
        print_text(line, col, text);
        Sleep(1000); // 暂停1000ms
    }
    return 0;
}
// 打印n个空格
void print_spaces(int n) {
    int i;
    for (i = 1; i <= n; ++i)
        printf(" ");
}
// 打印n行空白行
void print_blank_lines(int n) {
    int i;
    for (i = 1; i <= n; ++i)
        printf("\n");
}
// 在第line行第col列打印一段文本
void print_text(int line, int col, char text[]) {
    print_blank_lines(line - 1); // 打印(line-1)行空行
    print_spaces(col - 1); // 打印(col-1)列空格
    printf("%s", text); // 在第line行、col列输出text中字符串
}

#include <stdio.h>
long long fac(int n); // 函数声明
int main() {
    int i, n;
    printf("Enter n: ");
    scanf_s("%d", &n);
    for (i = 1; i <= n; ++i)
        printf("%d! = %lld\n", i, fac(i));
    return 0;
}
// 函数定义
long long fac(int n) {
    static long long p = 1;
    printf("p=%11d\n", p);
    p = p * n;
    return p;
}

#include <stdio.h>
long long func(int n); // 函数声明
int main() {
    int n;
    long long f;
    while (scanf_s("%d", &n) != EOF) {
        f = func(n); // 函数调用
        printf("n = %d, f = %lld\n", n, f);
    }
    return 0;
}
long long func(int n) {
    long long s;
    int i;
    if (n == 0)
        s = 0;
    else
    {
    
            s = (func(n - 1) + 1) * 2 - 1;
    }
        return s;
}

#include <stdio.h>
int func(int n, int m);
int main() {
    int n, m;
    while (scanf_s("%d%d", &n, &m) != EOF)
        printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    return 0;
}
int func(int n, int m) {
    int ans;
    if (n < m)
        ans = 0;
    else if (m == n)
        ans = 1;
    
    else if (m == 0)
        ans = 1;
    else
        ans = func(n - 1, m) + func(n - 1, m - 1);

    return ans;
}

#include <stdio.h>
int mul(int n, int m);
int main() {
    int n, m; 
    while (scanf_s("%d%d", &n, &m) != EOF)
        printf("%d * %d = %d\n", n, m, mul(n, m));
    return 0;
}
int mul(int n, int m)
{
    int i;
    int s=0;
    if (m == 0 || n == 0)
        s = 0;
    else
        for (i = 1; i <= m; i++)
            s = n+s;
    return s;
}

#include<stdio.h>
#include<stdlib.h>
void hanoi(unsigned int n, char from, char temp, char to);
void moveplate(unsigned int n, char from, char to);
int s;
int main()
{
    for (;;)
    {
        unsigned int n;
        s = 0;
        scanf_s("%u", &n);
        hanoi(n, 'A', 'B', 'C');
        printf("移动的次数为%d\n", s);
    }
    return 0;
}
void hanoi(unsigned int n, char from, char temp, char to)
{

    if (n == 1)
    {
        moveplate(n, from, to); s++;

    }
    else
    {
        hanoi(n - 1, from, to, temp);
        moveplate(n, from, to); s++;
        hanoi(n - 1, temp, from, to);

    }
}
void moveplate(unsigned int n, char from, char to)
{
    printf("%u:%c-->%c\n", n, from, to);
}

#include<stdio.h>
#include<math.h>
int is_prime();
int is_prime(int n)
{
    int i;
    for (i = 2; i <= n / 2; i++)
        if (n % i == 0)
            return 0;
    return 1;
}
int main()
{
    int h;
    int t;
    for (h=4; h <= 20; h = 2+h)
    {
        for (t=2; t <= h; t++)
        {
            if (is_prime(t) && is_prime(h - t) && t >= 2 && (h - t) >= 2)
                printf("%d=%d+%d\n", h, t, h - t);
        }
    }
    
}

#include <stdio.h>
#include<math.h>
long fun(long s); // 函数声明
int main() {
    long s, t;
    printf("Enter a number: ");
    while (scanf_s("%ld", &s) != EOF) {
        t = fun(s); // 函数调用
        printf("new number is: %ld\n\n", t);
        printf("Enter a number: ");
    }
    return 0;
}
long fun(long s)
{
    
    int a[100];
    int k=0;int j=0;
while(s>0)
    {
        int t;
        t = s % 10;
        if (t % 2 != 0)
        {
            a[j] = t;
            k = k + a[j] * pow(10.0, j);
            j++;
            s = s / 10;
        }
        else
            s = s / 10;
    }

    return k;
}