实验2 C语言控制语句应用编程

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

#define N 5

int main()
{
    int number;
    int i;

    srand(time(0));

    for (i = 0; i < N; ++i) {
        number = rand() % 500 + 1;
        printf("20228329%04d\n", number);

    }
    return 0;
}

#include<stdio.h>
#include<stdlib.h>
int main()
{
    int day, x, i;
    day = rand() % 30+1;

    printf("猜猜2022年11月那一天是你的lucky day\n");
    printf("开始咯,你有3次机会,猜吧(1~30):");
    
    for (i = 1; i <= 3; i++)
    {
        scanf_s("%d", &x);
        if (x > day)
        {

            printf("你猜的日期晚了,你的lucky day已经过啦\n"); continue;
        }
        else if (x < day)
        {

            printf("你猜的日期早了,你的lucky day还没到呢\n"); continue;
        }
        else if (x == day)
        {

            printf("哇,猜中了:)"); break;
        }
        
    }if(x!=day)
        printf("次数用完啦,偷偷告诉你:11月,你的lucky day是%d号", day);
    return 0;



}

#include<stdio.h>
#include<stdlib.h>
int main()
{char x;
    for (;;)
    {
    
    scanf_s("%c", &x);
    getchar();
        switch (x)
        {

        case 'r':printf("stop!\n"); break;
        case 'g':printf("go go go\n"); break;
        case 'y':printf("wait a minute\n"); break;
        default:printf("some thing must be wrong...");
        }

    }

#include<stdio.h>
#include<math.h>
int main() {
    for (;;) {
        long double n, a;
        long double s = 0.0000000000;
        scanf_s("%lf%lf", &n, &a);
        int i = 1;
        for (i = 1; i <= n; i++)
        {
            s = s + i / pow(a, i);
        }
        printf("s=%lf", s);
        printf("\n");
    }
    return 0;

#include<stdio.h>
#include<math.h>
int main()
{
    int a, b, sum;
    
    for (a = 1; a <= 9; a++)
    {
        for (b = 1; b <= 9; b++)
        {
            if (b <= a)
            {sum = a * b;
                printf("%d*%d=%d\t", a, b, sum);
                
            }
        }
    printf("\n");}
    return 0;
}

#include<stdio.h>
int main()
{
    int n, i,m;
    printf("Input n:\n");
    scanf_s("%d", &n);

    for (i = 1; i <= n; i++)
    {for (m = 1; m <= (i-1); m++)
        {
            printf("\t");
        }
        for (m = 1; m <= (2 * n - 2*i+1); m++)
        {
            printf(" 0 \t");
            
        }
        
        printf("\n");
        for (m = 1; m <= (i-1); m++)
        {
            printf("\t");
        }for (m = 1; m <= (2 * n - 2 * i + 1); m++)
        {

            printf("<H>\t");
            
        }    
        printf("\n");
        for (m = 1; m <= (i-1); m++)
        {
            printf("\t");
        }for (m = 1; m <= (2 * n - 2 * i + 1); m++)
        {

            printf("I I\t");
            
        }
        printf("\n");
        
    }
return 0;
}

 

posted @ 2022-10-25 10:24  殷正阳  阅读(47)  评论(0)    收藏  举报