实验六

task 4

源代码：

#include<stdio.h>
#define N 10

typedef struct{
    char isbn[20];
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
}Book;

void output(Book x[],int n);
void sort(Book x[],int n);
double sales_amount(Book x[],int n);

int main(){
    Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, 
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
                  
    printf("图书销量排名（按销量册数）：\n");
    sort(x,N);
    output(x,N);
    
    printf("\n图书销量总额：%.2f",sales_amount(x,N));
    
    return 0;
}

void output(Book x[],int n){
    int i;
    printf("%-20s %-30s %-20s %10s %10s\n","ISBN号","书名","作者","售价","销量");
    for(i = 0;i <n;i++)
        printf("%-20s %-30s %-20s %10.2f %10d\n",
               x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}

void sort(Book x[],int n){
    int i,j;
    Book temp;
    for(i = 0;i < n;i++){
        for(j = 0;j < n-1-i;j++){
            if(x[j].sales_count < x[j+1].sales_count){
                temp = x[j];
                x[j] = x[j+1];
                x[j +1] = temp;
            }
        }
    }
}

double sales_amount(Book x[],int n){
    double total = 0.0;
    int i;
    for(i = 0;i < n;i++)
        total += x[i].sales_price * x[i].sales_count;
    
    return total;

}

运行结果：

task 5

源代码：

#include<stdio.h>

typedef struct{
    int year;
    int month;
    int day;
}Date;

void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1,Date d2);

void test1(){
    Date d;
    int i;
    
    printf("输入日期：（以形如2025-12-19这样的形式输入）\n");
    for(i = 0;i < 3;i++){
        input(&d);
        printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
    }
}

void test2(){
    Date Alice_birth,Bob_birth;
    int i;
    int ans;
    
    printf("输入Alice和BOb出生日期：（以形如2025-12-19这样的形式输入）\n");
    for(i = 0;i < 3;++i){
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth,Bob_birth);
        
        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}

int main(){
    printf("测试1：输入日期，打印输出这一年中第多少天\n");
    test1();
    
    printf("测试2：两人年龄大小关系\n");
    test2();
}

void input(Date *pd){
    scanf("%d-%02d-%02d",&pd->year,&pd->month,&pd->day);
}

int day_of_year(Date d){
    int common_month_days[] = {31,28,31,30,31,30,31,31,30,31,30,31};
    int leap_month_days[] = {31,29,31,30,31,30,31,31,30,31,30,31};
    int total = 0;
    int i;
    
    if((d.year % 4 == 0 && d.year % 100!= 0)||(d.year % 400 == 0)){
        for(i = 0;i < d.month - 1;i++)
            total += leap_month_days[i];
    }
    else{
        for(i = 0;i < d.month - 1;i++)
            total += common_month_days[i];
    }
    total = total + d.day;
    return total;
}

int compare_dates(Date d1,Date d2){
    if(d1.year < d2.year)
        return -1;
    else if(d1.year > d2.year)
        return 1;
    else{
        if(d1.month < d2.month)
            return -1;
        else if(d1.month > d2.month)
            return 1;
        else{
            if(d1.day < d2.day)
                return -1;
            else if(d1.day > d2.day)
                return 1;
            else
                return 0;
        }
    }
}

运行结果：

task 6

源代码：

#include<stdio.h>
#include<string.h>

enum Role{admin,student,teacher};

typedef struct{
    char username[20];
    char password[20];
    enum Role type;
}Account;

void output(Account x[],int n);

int main(){
    Account x[] = {{"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student}, 
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student}};
    int n;
    n = sizeof(x)/sizeof(Account);
    output(x,n);
    
    return 0;
}

void output(Account x[],int n){
    int i,j;
    for(i = 0;i < n;i++){
        int len = strlen(x[i].password);
        for(j = 0;j < len;j++)
            x[i].password[j] = '*';
        printf("%-20s%-20s",x[i].username,x[i].password);
        switch(x[i].type){
            case 0:printf("admin\n");break;
            case 1:printf("student\n");break;
            case 2:printf("teacher\n");break;
            default:break;
        }
    }
}

运行结果：

task 7

源代码：

#include<stdio.h>
#include<string.h>

typedef struct{
    char name[20];
    char phone[12];
    int vip;
}Contact;

void set_vip_contact(Contact x[],int n,char name[]);
void output(Contact x[],int n);
void display(Contact x[],int n);

#define N 10
int main(){
    Contact list[N] = {{"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0}};
    int vip_cnt,i;
    char name[20];
    
    printf("显示原始通讯录信息：\n");
    output(list,N);
    
    printf("\n输入要设置的紧急联系人个数：");
    scanf("%d",&vip_cnt);
    printf("输入%d个紧急人联系人姓名：\n",vip_cnt);
    for(i = 0;i < vip_cnt;++i){
        scanf("%s",name);
        set_vip_contact(list,N,name);
    } 
    
    printf("\n显示通讯录列表：（按姓名字典序升序排列，紧急联系人最先显示）\n");
    display(list,N);
    
    return 0;
}

void set_vip_contact(Contact x[],int n,char name[]){
    int i;
    for(i = 0;i < n;i++){
        if(strcmp(x[i].name,name) == 0)
            x[i].vip = 1;
    }
}

void display(Contact x[],int n){
    int i,j;
    Contact temp;
    
    for(i = 0;i < n;i++){
        for(j = 0;j < n-1-i;j++){
            if(strcmp(x[j].name,x[j].name)> 0){
                temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
    
    for(i = 0;i < n;i++){
        for(j = 0;j < n-1-i;j++){
            if(x[j].vip == 0 && x[j+1].vip == 1){
                temp = x[j];
                x[j] = x[j+1];
                x[j+1] = temp;
            }
        }
    }
    output(x,n);
}

void output(Contact x[],int n){
    int i;
    
    for(i = 0;i < n;++i){
        printf("%-10s%-15s",x[i].name,x[i].phone);
        if(x[i].vip)
            printf("%5s","*");
        printf("\n");
    }
}

运行结果：