第六周上机作业
1.使用for循环计算1-100的和,除了以3结尾的那些数
package fgjkg;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
int sum=0;
for (int i = 1; i <=100; i++) {
if(i%10!=3)
sum+=i;
}
System.out.println("和是"+sum);
}
}

2.使用二重循环输出以下图形
*
***
*****
*******
*****
****
***
**
*
package fgjkg;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
int sum=0;
for (int i = 1; i < 5; i++) {
for (int c = 1; c < 5-i; c++) {
System.out.print(" ");
}
for (int j = 0; j < 2*i-1; j++) {
System.out.print("*");
}
System.out.println("");
}
System.out.println();
System.out.println();
for (int k = 0; k <6; k++) {
for (int b = 1; b < 6-k; b++) {
System.out.print("*");
}
System.out.println(" ");
}
}
}

3.循环输入学生姓名,直到输入‘Q’程序结束
4.输入5个学生成绩,求和,当输入不合法<0 >100的时候,提示输入错误重新输入。
package fgjkg;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input=new Scanner(System.in);
int sum=0;
for (int i = 0; i <=4; i++) {
System.out.println("请输入第"+(i+1)+"个学生额成绩");
int a=input.nextInt();
if(a>100||a<0) {
System.out.println("输入不合法请重新输入");
a=input.nextInt();
}
else {
sum+=a;
}
}
System.out.println("学生总成绩是"+sum);
}
}

5.计算 1+1/(1+2) + 1/(1+2+3) +1/(1+2+3+4)+…………+1/(1+2+....+10)
package 第六周;
package fgjkg;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input=new Scanner(System.in);
double sum=0;
double x=0;
for (int i = 01; i <11; i++) {
x=x+i;
sum=sum+1/x;
}
System.out.println(sum);
}
}

6.产生一个1-99的随机数,猜数字,若大了就提示“大了点”,若小了就提示“小了点”直到猜对为止。
(判断猜的次数,如果1-3次,提示太棒了 如果5-8次 一般般 如果8次以上 太笨了)
package 作业2;
package fgjkg;
import java.util.Random;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
Random random = new Random();
int x = random.nextInt(101);
int num=0;
while (true) {
num++;
System.out.println("请输入");
int i = input.nextInt();
if (i > x)
System.out.println("大了点");
else if (i < x)
System.out.println("小了点");
else {
System.out.println("答对了");
break;
}
}
System.out.println("一共猜了"+num+"次");
if(num<=3) {
System.out.println("太棒了 ");
}else if(num>3&&num<=8) {
System.out.println("一般般");
}else {
System.out.println("太笨了");
}
}
}

7输入一个数,判断是不是质数(只能被1和自身整除的数是质数)
package fgjkg;
import java.util.Random;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc=new Scanner(System.in);
int n,i=2,a=0;
System.out.println("请输入一个数:");
n=sc.nextInt();
while(i<=n-1)
{
if(n%i==0)
{
a=1;
break;
}
i++;
}
if(a==0)
System.out.println(n+"是质数");
else
System.out.println(n+"不是质数");
}
}

8.求裴波那契数列的第20项是什么。裴波那契数列,1,1,2,3,5,8,13,21……
package fgjkg;
import java.util.Random;
import java.util.Scanner;
public class dfger {
public static void main(String[] args) {
// TODO Auto-generated method stub
int a=1;
int b=1;
int c=0;
for(int i=1;i<=18;i++){
c=a+b;
a=b;
b=c;
}
System.out.println("第二十项"+c);
}
}

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