2024.3.12

第六天

所花时间:2小时

代码量:100+

博客量:1

了解到的知识点:今天上课老师让我们练习最长单词的查询,就是从哈利波特英文版的文件中读取并选出首尾相接的最长单词数,练习代码如下:

package file;

import java.io.*;
import java.util.*;


public class Piao {
public static void main(String[] args) throws FileNotFoundException, IOException {
// TODO 自动生成的方法存根

File file = new File("D:\\input1.txt");
File file2 = new File("D:\\output1.txt");


if (!file.exists()) {
System.out.println("文件不存在!");
} else if (file.exists() && file.length() == 0) {
System.out.println("文件为空!");
} //判断是否文件为空
else {
BufferedReader br = new BufferedReader(new FileReader(file));
BufferedWriter bw = new BufferedWriter(new FileWriter("D:/output1.txt"));


String s;
int i, j;
ArrayList<ArrayList<String>> listall = new ArrayList();
String key;
s = br.readLine();
//将文本文件中的所有信息变为字符串
String[] s1 = s.split(" ");//以空格为分割划分每个单词
if (s1.length == 1)
System.out.println("单词数为1");
else {

for (i = 0; i < s1.length; i++) {
System.out.println(s1[i]);
}//测试录入

for (j = 0; j < s1.length; j++) {
ArrayList<String> list = new ArrayList<String>();
key = s1[j].substring(s1[j].length() - 1);
list.add(s1[j]);
System.out.println("key:" + key);
for (i = 1; i < s1.length; i++) {

if (key.equals(s1[i].substring(0, 1))) {
list.add(s1[i]);
key = s1[i].substring(s1[i].length() - 1);
} else
continue;
}
listall.add(list);
}
int max = 0;
int count = 0;

for (i = 0; i < listall.size(); i++) {
if (max < listall.get(i).size()) {
max = listall.get(i).size();
count = i;
}
}
System.out.println("排位" + count);
System.out.println("最长单词链为:");
for (i = 0; i < listall.get(count).size(); i++) {
System.out.println(listall.get(count).get(i));
bw.write(listall.get(count).get(i));
bw.write(" ");
}
br.close();
bw.close();
}
}
}

}

参考了一下学长学姐的代码进一步理解了一下

posted @ 2024-03-19 00:27  cvjj  阅读(9)  评论(0)    收藏  举报