OpenSSL测试-SM4

任务详情
0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务
1. 使用OpenSSL的命令对你的8位学号(数字)进行加密解密,密钥的前8个字节为你的8位学号,提交过程截图(5')
2. 使用OpenSSL编程对对"你的8位学号(数字)"进行加密解密,提交代码和运行结果截图。(10’)
3. 使用OpenSSL编程对内容为"所有同学的8位学号(数字)"的文件进行加密解密,密钥要包含你的8位学号,提交代码和运行结果截图。(选做(10’))
 

 

 1. 使用OpenSSL的命令对你的8位学号(数字)进行加密解密,密钥的前8个字节为你的8位学号

原始文件

 

 加密

 

 

解密

 

 

 

2. 使用OpenSSL编程对"你的8位学号(数字)"进行加密解密

 

3. 使用OpenSSL编程对内容为"所有同学的8位学号(数字)"的文件进行加密解密,密钥要包含你的8位学号

代码

#include <openssl/rsa.h>
#include <openssl/pem.h>
#include <openssl/err.h>
#include <openssl/evp.h>
#include <openssl/ec.h>
int main(int argc, char *argv[])
{
    unsigned char sm4_en[512],sm4_de[512];
    int sm4enStrLen,sm4deStrLen;
    unsigned char source[7]={0x31,0x33,0x34,0x33,0x45,0x46,0x43};
    unsigned char keyStr[16]={0x15,0x67,0x28,0xe1,0x5f,0x9a,0xfc,0x01,0xd4,0xb6,0x1b,0x4e,0x44,0x5d,0xbb,0x26};
    sm4enStrLen=my_sm4encrpt(keyStr,source,7,sm4_en);
    printf("sm4enStrLen:%d\n",sm4enStrLen);
    for(int i=0;i<sm4enStrLen;++i)
    {
        printf("0x%x",sm4_en[i]);
    }
    printf("\n");
    sm4deStrLen=dencryptStr(keyStr,sm4_en,sm4enStrLen,sm4_de);
    printf("sm4deStrLen:%d\n",sm4deStrLen);
    for(int i=0;i<7;++i)
    {
        printf("0x%x",sm4_de[i]);
    }
    printf("\n");
}
int my_sm4encrpt(unsigned char * keyStr,unsigned char * surbuf,int surlen,unsigned char * enbuf)
{
    unsigned char *out_buf = enbuf;
    int out_len;
    int out_padding_len;
    int i;
    unsigned char *iv;
    EVP_CIPHER_CTX *ctx;
    ctx = EVP_CIPHER_CTX_new();
    EVP_EncryptInit(ctx, EVP_sm4_ecb(), keyStr, iv);
    if( 0 == surlen % 16 )
    {
        EVP_CIPHER_CTX_set_padding( ctx, 0 );
    }
    out_len = 0;
    EVP_EncryptUpdate(ctx, out_buf, &out_len, surbuf, surlen);
    out_padding_len = 0;
    EVP_EncryptFinal(ctx, out_buf + out_len, &out_padding_len);
 
    EVP_CIPHER_CTX_free(ctx);
    return out_len + out_padding_len;
}
 
 
int dencryptStr(unsigned char * sm4PriKey, unsigned char *cEnStr, int cEnstrlen, unsigned char *deStr)
{
    unsigned char *iv;
    EVP_CIPHER_CTX *ctx;
    int len;
    int temlen;
    int deStrLen;
    if (!(ctx = EVP_CIPHER_CTX_new())) {
       printf("EVP_CIPHER_CTX_new failed");
    }
    if (1 != EVP_DecryptInit(ctx, EVP_sm4_ecb(), sm4PriKey, iv)) {
        printf("EVP_DecryptInit_ex failed");
    }
 
 
    if (1 != EVP_DecryptUpdate(ctx, deStr, &len, cEnStr, cEnstrlen)) {
        printf("EVP_DecryptUpdate failed");
    }
    if( 0 == len % 16 )
    {
        EVP_CIPHER_CTX_set_padding( ctx, 0 );
        len += 16;
 
    }
    if( !EVP_DecryptFinal( ctx, deStr + len, &temlen ) )
    {
        printf("EVP_DecryptFinal failed");
        return EXIT_FAILURE;
    }
    deStrLen=len+temlen;
    printf("解密数据:%d\n",deStrLen);
    for (int i = 0;i < deStrLen;i++) {
        printf("0x%02x ",*(deStr + i));
    }
    printf("\n");
    EVP_CIPHER_CTX_free(ctx);
    return deStrLen;
}

 

结果

 

 

 

posted @ 2023-04-12 10:07  20201208史逸霏  阅读(138)  评论(0编辑  收藏  举报