线性结构03--队列

数组实现:

typedef int Position;
struct QNode {
    ElementType *Data;     /* 存储元素的数组 */
    Position Front, Rear;  /* 队列的头、尾指针 */
    int MaxSize;           /* 队列最大容量 */
};
typedef struct QNode *Queue;
 
Queue CreateQueue( int MaxSize )
{
    Queue Q = (Queue)malloc(sizeof(struct QNode));
    Q->Data = (ElementType *)malloc(MaxSize * sizeof(ElementType));
    Q->Front = Q->Rear = 0;
    Q->MaxSize = MaxSize;
    return Q;
}
 
bool IsFull( Queue Q )
{
    return ((Q->Rear+1)%Q->MaxSize == Q->Front);
}
 
bool AddQ( Queue Q, ElementType X )
{
    if ( IsFull(Q) ) {
        printf("队列满");
        return false;
    }
    else {
        Q->Rear = (Q->Rear+1)%Q->MaxSize;
        Q->Data[Q->Rear] = X;
        return true;
    }
}
 
bool IsEmpty( Queue Q )
{
    return (Q->Front == Q->Rear);
}
 
ElementType DeleteQ( Queue Q )
{
    if ( IsEmpty(Q) ) { 
        printf("队列空");
        return ERROR;
    }
    else  {
        Q->Front =(Q->Front+1)%Q->MaxSize;
        return  Q->Data[Q->Front];
    }
}

 

链表实现:

typedef struct Node *PtrToNode;
struct Node { /* 队列中的结点 */
    ElementType Data;
    PtrToNode Next;
};
typedef PtrToNode Position;
 
struct QNode {
    Position Front, Rear;  /* 队列的头、尾指针 */
    int MaxSize;           /* 队列最大容量 */
};
typedef struct QNode *Queue;
 
bool IsEmpty( Queue Q )
{
    return ( Q->Front == NULL);
}
ElementType DeleteQ( Queue Q )
{
    Position FrontCell; 
    ElementType FrontElem;
     
    if  ( IsEmpty(Q) ) {
        printf("队列空");
        return ERROR;
    }
    else {
        FrontCell = Q->Front;
        if ( Q->Front == Q->Rear ) /* 若队列只有一个元素 */
            Q->Front = Q->Rear = NULL; /* 删除后队列置为空 */
        else                     
            Q->Front = Q->Front->Next;
        FrontElem = FrontCell->Data;
 
        free( FrontCell );  /* 释放被删除结点空间  */
        return  FrontElem;
    }
}
Queue Add(ElementType x,Queue Q){
PtrToNode N;
N=(PtrToNode)malloc(sizeof(PtrToNode));
N->Data=x;
N->Next=NULL;
Q->Rear->next=N;
Q->Rear=N;
return Q;
}

 

posted @ 2020-03-18 16:40  CurrentlyMe  阅读(111)  评论(0)    收藏  举报