go语言-不同类型转换为JSON格式数据

1.将结构体转换为JSON：

package main

import (
	"encoding/json"
	"fmt"
)

type Person struct {
	Name  string
	Age   int
	Email string
}

func main() {
	person := Person{Name: "Alice", Age: 25, Email: "alice@example.com"}

	jsonData, err := json.Marshal(person)
	if err != nil {
		fmt.Println("转换失败:", err)
		return
	}

	fmt.Println(string(jsonData))
}

2.将切片转换为JSON

package main

import (
	"encoding/json"
	"fmt"
)

func main() {
	numbers := []int{1, 2, 3, 4, 5}

	jsonData, err := json.Marshal(numbers)
	if err != nil {
		fmt.Println("转换失败:", err)
		return
	}

	fmt.Println(string(jsonData))
}
答案解析：

3.将Map转换为JSON　

package main

import (
	"encoding/json"
	"fmt"
)

func main() {
	student := map[string]interface{}{
		"name":   "Bob",
		"age":    20,
		"gender": "male",
	}

	jsonData, err := json.Marshal(student)
	if err != nil {
		fmt.Println("转换失败:", err)
		return
	}

	fmt.Println(string(jsonData))
}

4.将JSON字符串转换为结构体

package main

import (
	"encoding/json"
	"fmt"
)

type Person struct {
	Name  string
	Age   int
	Email string
}

func main() {
	jsonData := `{"Name":"Alice","Age":25,"Email":"alice@example.com"}`

	var person Person
	err := json.Unmarshal([]byte(jsonData), &person)
	if err != nil {
		fmt.Println("反序列化失败:", err)
		return
	}

	fmt.Printf("姓名：%s，年龄：%d，邮箱：%s\n", person.Name, person.Age, person.Email)
}

5.将JSON数组转换为切片：

go
package main

import (
	"encoding/json"
	"fmt"
)

func main() {
	jsonData := `[1,2,3,4,5]`

	var numbers []int
	err := json.Unmarshal([]byte(jsonData), &numbers)
	if err != nil {
		fmt.Println("反序列化失败:", err)
		return
	}

	fmt.Println(numbers)
}