LeetCode-Clone Graph
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
- First node is labeled as
0. Connect node0to both nodes1and2. - Second node is labeled as
1. Connect node1to node2. - Third node is labeled as
2. Connect node2to node2(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
class Solution { public: void Sub(map<UndirectedGraphNode*,UndirectedGraphNode*>& se,UndirectedGraphNode** nnode,UndirectedGraphNode*node){ (*nnode)=new UndirectedGraphNode(node->label); se[node]=(*nnode); for(int i=0;i<node->neighbors.size();i++){ if(se.find(node->neighbors[i])==se.end()){ UndirectedGraphNode * n; Sub(se,&n,node->neighbors[i]); (*nnode)->neighbors.push_back(n); } else{ (*nnode)->neighbors.push_back(se[node->neighbors[i]]); } } } UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) { // Note: The Solution object is instantiated only once and is reused by each test case. if(node==NULL)return NULL; UndirectedGraphNode * ret=NULL; map<UndirectedGraphNode *,UndirectedGraphNode*>se; Sub(se,&ret,node); return ret; } };
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