UVa 389 Basically Speaking

又一道基础题，进制转换。

做水题也不能大意！

 1 //68ms      2010-05-14 15:48:58
 2  //log: wa(1) ac(1)
 3 //Type: Base number conversion(进制转换)
 4 //key1: strrev() 在ANSI C, C++ 中不能使用
 5 //key2: 0的时候要处理
 6 //Thinking: After finished coding, member to try some special data.
 7 #include <stdio.h>
 8 #include <string.h>
 9 #define NL 100
10 
11 int get(char a)
12 {
13     if (a >= '0' && a <= '9') return a-'0';
14     return a-'A'+10;
15 }
16 
17 int main()
18 {
19     char s0[NL], s1[NL];
20     int len, I, K, M, b1, b2;
21     while (scanf("%s%d%d", s0, &b1, &b2) != EOF) {
22         len = strlen(s0);
23         int t = 0, bb = 1;
24         I = len - 1;
25         while (I>=0) {
26             t += get(s0[I])*bb;
27             bb *= b1;
28             I--;
29         }
30         K = 0;
31         while (t>0) {
32             I = t%b2;
33             if (I>=10) s1[K++] = I-10+'A';
34             else s1[K++] = I+'0';
35             t /= b2;
36         }
37         if (K == 0) { s1[K++] = '0'; }
38         s1[K] = '\0';
39         if (K > 7) puts("  ERROR");
40         else {
41             for (I=0, M=K-1; M>=0; M--) {
42                 s0[I++] = s1[M];
43             }
44             s0[I] = '\0';
45             printf("%7s\n", s0);
46         }
47     }
48     return 0;
49 }
50 /*
51 input:
52 0000000  2  2
53 */

 

posted @ 2010-05-14 15:50  superbin  阅读(616)  评论(0)    收藏  举报