十进制-二进制转换测试
//************************************ //程序名:十进制-二进制转换测试 //功 能:输入十进制数,输出对应的二进制码 // 其中二进制码用十进制的格式表示 //编制人:刘聪 //时 间:2017年5月26日 //************************************ #include <iostream> #include <cmath> using namespace std; int main() { int n, Binary; int DecimalToBinary(int n); cout<<"输入一个十进制整数:"; cin>>n; Binary = DecimalToBinary(n); cout<<"对应的二进制码为:"<<Binary<<endl; return 0; } int DecimalToBinary(int n) { int quotient, remainder, counter, Binary, i; counter = 0; quotient = 0; remainder = 0; Binary = 0; i = 0; while((quotient = n / 2 ) > 0) { remainder = n % 2; n = quotient; counter++; if(remainder == 1) { for(i = counter; i > 1; i--) remainder = remainder * 10; Binary = remainder + Binary; //cout<<"Binary1="<<Binary<<endl; } //cout<<"Binary2="<<Binary<<endl; } remainder = 1; counter++; for(i = counter; i > 1; i--) remainder = remainder * 10; Binary = remainder + Binary; return Binary; }
按此方法,在不溢出的前提下,最大能转换数值为511.
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posted on 2017-10-05 18:17 sunshineman1986 阅读(144) 评论(0) 编辑 收藏 举报