Swift JSON字符串和字典以及数组的互转

https://www.cnblogs.com/jukaiit/p/9345654.html

 

Swift JSON字符串和字典以及数组的互转

 

1、JSONString转换为字典

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// JSONString转换为字典   func getDictionaryFromJSONString(jsonString:String) ->NSDictionary{       let jsonData:Data = jsonString.data(using: .utf8)!       let dict = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)     if dict != nil {         return dict as! NSDictionary     }     return NSDictionary()         }

2、JSONString转换为数组

 

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func getArrayFromJSONString(jsonString:String) ->NSArray{                   let jsonData:Data = jsonString.data(using: .utf8)!                   let array = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)         if array != nil {             return array as! NSArray         }         return array as! NSArray               }

　　

3、字典转换为JSONString

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/**      字典转换为JSONString             - parameter dictionary: 字典参数             - returns: JSONString      */     func getJSONStringFromDictionary(dictionary:NSDictionary) -> String {         if (!JSONSerialization.isValidJSONObject(dictionary)) {             print("无法解析出JSONString")             return ""         }         let data : NSData! = try? JSONSerialization.data(withJSONObject: dictionary, options: []) as NSData!         let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)         return JSONString! as String       }

　

4、数组转换为JSONString

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//数组转json func getJSONStringFromArray(array:NSArray) -> String {           if (!JSONSerialization.isValidJSONObject(array)) {         print("无法解析出JSONString")         return ""     }           let data : NSData! = try? JSONSerialization.data(withJSONObject: array, options: []) as NSData!     let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)     return JSONString! as String       }