掉入陷阱的数字

掉入陷阱的数字

/problem-sets/1325975206586703872/problems/1325979500962603012

#include<stdio.h>
int main(void)
{
	int N,Last,All_digit_sum,i;
	scanf("%d",&N);
	for(i=1;-1;i++)
	{
		printf("%d:",i);
		All_digit_sum = N%10+N/10%10+N/100%10+N/1000%10+N/10000;
		Last = N;
		N = All_digit_sum*3+1;
		printf("%d\n",N);
		if(Last==N)break;
	}
	return 0;
} 

posted @ 2020-11-11 16:36  summeriver13  阅读(38)  评论(0)    收藏  举报