写出这个数

题源

PTA 乙级

题解

#include<stdio.h>
void pinyin(int x){
	switch(x)
	{
		case 0:	printf("ling");	break;
		case 1:	printf("yi");	break;
		case 2:	printf("er");	break;
		case 3:	printf("san");	break;
		case 4:	printf("si");	break;
		case 5:	printf("wu");	break;
		case 6:	printf("liu");	break;
		case 7:	printf("qi");	break;
		case 8:	printf("ba");	break;
		case 9:	printf("jiu");	break;
	}
}
int main(void){
	char c;
	int sum = 0;
	c = getchar();
	for(;c != '\n';){
		sum += c - 48;
		c = getchar();
	}
	int n1,n2,n3;
	n1 = sum / 100;
	if(sum/100 != 0)
		n2 = sum / 10 % 10;
	else
		n2 = sum / 10;
	n3 = sum % 10;
	if(n1 != 0){
		pinyin(n1);
		printf(" ");
		pinyin(n2);
		printf(" ");
		pinyin(n3);
	}
	if(n1 == 0 && n2 != 0){
		pinyin(n2);
		printf(" ");
		pinyin(n3);
	}
	if(n1 == 0 && n2 == 0){
		pinyin(n3);
	}
//    printf("sum = %d\n",sum);
	return 0;
}