面向对象综合练习题（动物乐园）

动物乐园

 

任务描述：

  以面向对象思想设计动物乐园系统

  动物乐园包括的成员：猫、鸭子，海豚，……

  属性：名称、腿

  方法：叫

  设计类图

  使用多态、接口优化设计

 

 

  编码实现

分别创建Cat、Duck、Dolphin对象并放到一个数组中，对数组进行遍历输出各种动物如何叫，各种动物腿的条数。instanceof判断动物种类      。

 

package com.Summer_0428.cn;

abstract class Animal1{
    private String name;
    public Animal1(String name) {
        this.name = name;
    }
    
    public String getName() {
        return name;
    }
    public abstract void show();//定义一个抽象方法
}

interface Terrestrial{
    public int getLegNum();
}

class Cat1 extends Animal1 implements Terrestrial{
    private int legNum;
    public Cat1(String name,int legNum) {
        super(name);
        this.legNum = legNum;
    }

    @Override
    public int getLegNum() {
        return legNum;
    }
    
    @Override
    public void show() {
        System.out.println("喵喵喵");
    }
    
}

class Duck extends Animal1 implements Terrestrial{
    private int legNum;
    public Duck(String name,int legNum) {
        super(name);
        this.legNum = legNum;
    }

    @Override
    public int getLegNum() {
        return legNum;
    }
    
    @Override
    public void show() {
        System.out.println("嘎嘎嘎");
    }
    
}

class Dolphin extends Animal1 {

    public Dolphin(String name) {
        super(name);
    }
    
    @Override
    public void show() {
        System.out.println("海豚音");
    }
    
}
public class Zoo {

    public static void main(String[] args) {
        Animal1 animals[] = new Animal1[3];
        animals[0] = new Cat1("加菲猫", 4);
        animals[1] = new Duck("唐小鸭", 2);
        animals[2] = new Dolphin("海豚奇奇");
        
        System.out.println("动物名字\t\t腿的条数\t\t动物叫");
        for (int i = 0; i < animals.length; i++){
            if (animals[i] instanceof Terrestrial) {
                String name = animals[i].getName();
                int legNum = ((Terrestrial) animals[i]).getLegNum();
                System.out.print(name + "\t\t" + legNum + "\t\t");
                animals[i].show();
            } else {
                String name = animals[i].getName();
                System.out.print(name + "\t\t" + 0 + "\t\t");
                animals[i].show();
            }
        }
        

    }

}