Like的模糊查询

 sqlsrv：

$UploaderID = strval( $_GET[ 'UploaderID' ] );

 

///防止参数乱码
$UploaderID = iconv( "UTF-8", "GB2312//IGNORE", $UploaderID );

 

////sql语句

$sql = "SELECT
*
FROM
StandardResources
WHERE
UploaderID
like '%".$UploaderID."%' ";

//// 参数
$params = array( $UploaderID );

 

 

oracle :

  select * from table_name where 1=1 

 <#if secondName?? && secondName?has_content> 

  and second_name like '%'||:secondName||'%'

</#if>

 

mysql:

　select * from table_name where 1=1 

 <#if secondName?? && secondName?has_content> 

  and second_name like concat('%', :second_name ,'%')

</#if>