[LeetCode] 26. Remove Duplicates from Sorted Array ☆

 

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn't matter what you leave beyond the new length.

 

解法:

  这道题让我们移除一个数组中和给定值相同的数字,并返回新的数组的长度。是一道比较容易的题,我们只需要一个变量用来计数,然后遍历原数组,如果当前的值和给定值不同,我们就把当前值覆盖计数变量的位置,并将计数变量加1。代码如下:

public class Solution {
    public int removeDuplicates(int[] nums) {
        if (nums == null || nums.length == 0) {
            return 0;
        }
        
        int newLength = 1;
        for (int i = 1; i < nums.length; i++) {
            if (nums[i] != nums[i - 1]) {
                nums[newLength++] = nums[i];
            }
        }
        return newLength;
    }
}

 

posted @ 2017-02-20 16:47  Strugglion  阅读(123)  评论(0编辑  收藏  举报