prove function f has boundry in [a,b],if f is continuous in [a,b], using finite covering, and compact theorem

prove:
by "contiunuous function has local boundry",\(\forall x\in [a,b]\)
exists a \(\delta\) and M, for all \(x\in\U(x;\delta)\),x\(\leqslant<M\)
the set H={U;x}

posted @ 2020-08-31 10:56  strongdady  阅读(131)  评论(0编辑  收藏  举报