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[Swift]LeetCode226. 翻转二叉树 | Invert Binary Tree

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Invert a binary tree.

Example:

Input:

     4
   /   \
  2     7
 / \   / \
1   3 6   9

Output:

     4
   /   \
  7     2
 / \   / \
9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so f*** off.

 

 

翻转一棵二叉树。

示例：

输入：

     4
   /   \
  2     7
 / \   / \
1   3 6   9

输出：

     4
   /   \
  7     2
 / \   / \
9   6 3   1

备注:
这个问题是受到 Max Howell 的 原问题 启发的 ：

谷歌：我们90％的工程师使用您编写的软件(Homebrew)，但是您却无法在面试时在白板上写出翻转二叉树这道题，这太糟糕了。

 

12ms

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     public var val: Int
 5  *     public var left: TreeNode?
 6  *     public var right: TreeNode?
 7  *     public init(_ val: Int) {
 8  *         self.val = val
 9  *         self.left = nil
10  *         self.right = nil
11  *     }
12  * }
13  */
14 class Solution {
15     func invertTree(_ root: TreeNode?) -> TreeNode? {
16         guard let root = root else {return nil}
17         let left = invertTree(root.left)
18         let right = invertTree(root.right)
19         root.left = right
20         root.right = left
21         return root
22     }
23 }

8ms

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     public var val: Int
 5  *     public var left: TreeNode?
 6  *     public var right: TreeNode?
 7  *     public init(_ val: Int) {
 8  *         self.val = val
 9  *         self.left = nil
10  *         self.right = nil
11  *     }
12  * }
13  */
14 class Solution {
15     func invertTree(_ root: TreeNode?) -> TreeNode? {
16         if root == nil {
17             return root
18         }else{
19             let temp = root?.left
20             root?.left = invertTree(root?.right)
21             root?.right = invertTree(temp)
22             return root
23         }
24     }
25 }

12ms

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     public var val: Int
 5  *     public var left: TreeNode?
 6  *     public var right: TreeNode?
 7  *     public init(_ val: Int) {
 8  *         self.val = val
 9  *         self.left = nil
10  *         self.right = nil
11  *     }
12  * }
13  */
14 class Solution {
15     func invertTree(_ root: TreeNode?) -> TreeNode? {
16         if root == nil {
17         return root
18     }
19     
20     var temp: TreeNode?
21     
22     if root?.left?.left != nil || root?.left?.right != nil {
23         temp = invertTree(root?.left)
24     }else {
25         temp = root?.left
26     }
27     if (root?.right?.left != nil || root?.right?.right != nil ){
28         root?.left = invertTree(root?.right)
29     }else {
30         root?.left = root?.right
31     }
32     root?.right = temp
33     
34     return root
35         
36     }
37 }

 

posted @ 2018-10-06 18:37  为敢技术  阅读(406)  评论(0)  编辑  收藏  举报