poj 2350（水题）

#include<iostream>
using namespace std;
int main(){
    int c,n,i,j,t;
    int data[1005];
    double sum;
    scanf("%d",&c);
    while(c--){
        scanf("%d",&n);
        sum = 0;
        for(i=0;i<n;i++){
            scanf("%d",&data[i]);
            sum += data[i];
        }
        sum /= n;
        t = 0;
        for(i=0;i<n;i++){
            if(data[i]>sum){
                t++;
            }
        }
        printf("%.3lf%c\n",100.0*t/n,'%');
    }
    return 0;
}