poj 1528(水题)

#include<iostream>
using namespace std;
int main(){
    int i,j,data[105],cnt = 0,t,ans[105];
    while(scanf("%d",&data[cnt])==1&&data[cnt]!=0){
        t = 0;
        for(i=1;i<=data[cnt]/2;i++){
            if(data[cnt]%i==0){
                t += i;
            }
        }
        if(t==data[cnt]){
            ans[cnt] = 0;
        }
        if(t<data[cnt]){
            ans[cnt] = -1;
        }
        if(t>data[cnt]){
            ans[cnt] = 1;
        }
        cnt++;
    }
    printf("PERFECTION OUTPUT\n");
    for(i=0;i<cnt;i++){
        printf("%5d  ",data[i]);
        if(ans[i]==0)printf("PERFECT\n");
        if(ans[i]==-1)printf("DEFICIENT\n");
        if(ans[i]==1)printf("ABUNDANT\n");
    }
    printf("END OF OUTPUT\n"); 
    return 0;
}

 

posted @ 2021-11-14 17:39  智人心  阅读(29)  评论(0)    收藏  举报