poj 2583(水题)

#include<iostream>
#include<cstdio>
using namespace std;
int main(){
    int k1,k2,k3,a[3];
    while(scanf("%d%d%d",&k1,&k2,&k3)==3){
        a[0] = k1-3*k2+3*k3;
        a[1] = 3*k1-8*k2+6*k3;
        a[2] = 6*k1-15*k2+10*k3;
        printf("%d %d %d\n",a[0],a[1],a[2]);
    }
    return 0;
}

 

posted @ 2021-07-31 20:48  智人心  阅读(25)  评论(0)    收藏  举报