机器人跳跃问题

https://www.nowcoder.com/exam/test/65717435/detail?pid=16516564&examPageSource=Company&testCallback=https%3A%2F%2Fwww.nowcoder.com%2Fexam%2Fcompany%3FcurrentTab%3Drecommand%26jobId%3D100%26selectStatus%3D0%26tagIds%3D665&testclass=%E8%BD%AF%E4%BB%B6%E5%BC%80%E5%8F%91

找规律，发现每次跳跃到下一阶段，能量都会变为：2*E-H(k+1)

#include <iostream>

#include <vector>

using namespace std;

int main() {

    int N;

    cin>>N;

    vector<int> H(N+1,0);

    int i = 1;

    while (cin >> H[i++]) { // 注意 while 处理多个 case

    }

    long long res = 0;

    for(i= N;i>0;i--){

        res = res + H[i];

        res = (res + 1) / 2;

    }

    cout<<res<<'\n';

    return 0;

}

// 64 位输出请用 printf("%lld")