登录后保存用户信息到Session

 

前端通过JS把用户信息传到Controller，然后在Controller里将信息放入HttpSession中

1.  
   @ResponseBody
2.  
   @RequestMapping(value = "/loginIn", method = RequestMethod.POST, produces = "application/json;charset=UTF-8")
3.  
   public String loginIn(HttpServletRequest request, HttpSession httpSession) {
4.  
   String loginuser = request.getParameter("username");
5.  
   String pwd = request.getParameter("password");
6.  
   logger.info("loginuser:" + loginuser + ",pwd:" + pwd);
7.  
   JSONObject jsonObject = userFacade.loginIn(loginuser, pwd);
8.  
   // 将用户保存到session内
9.  
   if ("0".equals(jsonObject.getString("ecode"))) {//判断不用管
10.  
    httpSession.setAttribute("username", loginuser);
11.  
    httpSession.setAttribute("password", pwd);
12.  
    }
13.  
    return FastJsonConvert.convertObjectToJSON(jsonObject);
14.  
    }

再在前端js中调用Controller第二个方法，获取session内容

JS中代码：

1.  
   var username = "";
2.  
   $.ajax({
3.  
   "url" : "getUserSession",
4.  
   "method" : "POST",
5.  
   "cache" : false,
6.  
   "async" : false,
7.  
   }).success(function(data){
8.  
   if(data.username != null){
9.  
   username = data.username;
10.  
    }
11.  
    })

Controller获取代码：（return JSON对象）

 

1.  
   @ResponseBody
2.  
   @RequestMapping(value = "/getUserSession", method = RequestMethod.POST, produces = "application/json;charset=UTF-8")
3.  
   public String getUserSession(HttpServletRequest request, HttpSession httpSession) {
4.  
   JSONObject jsonObject = new JSONObject();
5.  
   if(httpSession!=null){
6.  
   jsonObject.put("username", httpSession.getAttribute("username"));
7.  
   jsonObject.put("password", httpSession.getAttribute("password"));
8.  
   }
9.  
   return FastJsonConvert.convertObjectToJSON(jsonObject);
10.  
    }

这样就可把user信息保存到session中，并返回到前端