Access数据库中Round用法

Access数据库中Round用法

四舍五入的问题

select round(83.124,2) as t from jqdltb

显示为:83.12


select round(83.125,2) as t from jqdltb

显示为:83.12


select round(83.126,2) as t from jqdltb

显示为:83.13

问题来了,就是四舍五入怎么变成五舍六入了呢?

下面是用这个方法来调整达到四舍五入的方法:

使用int函数和加0.005,然后*100,再然后/100

如下所示:

select int((83.121+0.005)*100)/100 as t from jqdltb

显示为:83.12


select int((83.124+0.005)*100)/100 as t from jqdltb

显示为:83.12


select int((83.125+0.005)*100)/100 as t from jqdltb

显示为:83.13


select int((83.126+0.005)*100)/100 as t from jqdltb

显示为:83.13


select int((83.129+0.005)*100)/100 as t from jqdltb

显示为:83.13


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---create date:2012-03-30----




posted @ 2012-03-30 18:12  sqlite例子  阅读(831)  评论(0)    收藏  举报