【IT面试题003】将一个正整数写成若干个整数之和
将一个正整数写成若干个整数之和,打印出所有的可能,每种和输出时,加数升序排列
#include <iostream>
#include <string>
#include <vector>
using namespace std;
vector<int> solution;
int gNum; //目前的加数个数
int gCurSum; //当前和
int gN; //目标和
int gSolCount;
void PrintSolution()
{
for (int i = 0;i < gNum;i++)
{
cout << solution[i] << " ";
}
cout << endl;
}
void Go()
{
if (gCurSum == gN)
{
gSolCount ++;
PrintSolution();
return;
}
int lastAdd = 1; // 从1开始
if (gNum > 0)
{
lastAdd = solution[gNum - 1];
}
if (lastAdd > (gN - gCurSum)) //如果最小的可行加数都大于剩余和,就不要继续了
{
return;
}
for (int adder = lastAdd;adder <= (gN - gCurSum); adder++)
{
gCurSum += adder;
gNum ++;
if (solution.size() >= gNum)
{
solution[gNum - 1] = adder;
}else{
solution.push_back(adder);
}
Go();
//回溯
gCurSum -= adder;
gNum --;
}
}
int _tmain(int argc, _TCHAR* argv[])
{
gN = 10;
gSolCount = 0;
gCurSum = gNum = 0;
Go();
cout << gSolCount << endl;
}
posted on 2011-06-04 17:57 speedmancs 阅读(345) 评论(0) 收藏 举报
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