C# 获取属性的displayName

public static Dictionary<string, decimal?> DisplayNameModel<T>(T t)
        {
            Type type = typeof(T);
            PropertyInfo[] properties = type.GetProperties();
            Dictionary<string, decimal?> dic = new Dictionary<string, decimal?>();
            foreach (var p in properties)
            {
                //display名字
                var name = p.GetCustomAttribute<DisplayNameAttribute>().DisplayName;
                //对应的值
                var value = t.GetType().GetProperty(p.Name).GetValue(t, null);
                dic.Add(name, Convert.ToDecimal(value));
            }
            return dic;
        }

　　

1. public static Dictionary<string, decimal?> DisplayNameModel<T>(T t)
2.  
   {
3.  
   Type type = typeof(T);
4.  
   PropertyInfo[] properties = type.GetProperties();
5.  
   Dictionary<string, decimal?> dic = new Dictionary<string, decimal?>();
6.  
   foreach (var p in properties)
7.  
   {
8.  
   //display名字
9.  
   var name = p.GetCustomAttribute<DisplayNameAttribute>().DisplayName;
10.  
    //对应的值
11.  
    var value = t.GetType().GetProperty(p.Name).GetValue(t, null);
12.  
    dic.Add(name, Convert.ToDecimal(value));
13.  
    }
14.  
    return dic;
15.  
    }